What is 0.00996 written in scientific notation

Chemistry

1 answer:

Troyanec [42]3 years ago

7 0

0.00996 in scientific notation is 0.0996e-1.

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A combustion analysis of 5.214 g of a compound yields 5.34 g co 2 , 1.09 g h 2 o, and 1.70 g n 2 . if the molar mass of th

nekit [7.7K]

Answer is: C₃H₃N₃O₃.
Chemical reaction: CₓHₓNₓOₓ + O₂ → aCO₂ + x/2H₂ + x/2N₂.
m(CₐHₓNₓ) = 5,214 g.
m(CO₂) = 5,34 g.
m(H₂) = 1,09 g.
m(N₂) = 1,70 g.
n(CO₂) = n(C) = 5,34 g ÷ 44 g/mol = 0,121 mol.
n(H₂O) = 1,09 g ÷18 g/mol = 0,06 mol.
n(H) = 2 · 0,0605 mol = 0,121 mol.
n(N₂) = 1,7 g ÷ 28 g/mol = 0,0607 mol.
n(N) = 0,0607 mol · 2 = 0,121 mol.
n(C) : n(H) : n(N) = 0,121 mol : 0,121 mol : 0,121 mol /: 0,121
n(C) : n(H) : n(N) = 1 : 1 : 1.
M(CHN) = 27 g/mol.
m(O₂) = 8,13 g - 5,214 g = 2,914 g.
n(O₂) = 2,914 g ÷ 32 g/mol = 0,09 mol.
n(CₓHₓNₓOₓ) = 5,214 g ÷ 129,1 g/mol = 0,0404 mol.
n(CₓHₓNₓOₓ) : n(CO₂) = 1 : 3.

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3 years ago

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Match the salt with the acid and base used to form it in a neutralizing reaction.

nignag [31]

<h3><u>Answer;</u></h3>

K2SO4 - KOH and H2SO4

NaBr - NaOH and HBr

<h3><u>Explanation;</u></h3>

Salts are compounds that contain positively charged ions and negatively charged ions. That is; they consist of the positive ion of a base and the negative ion of an acid.
Salts may be produced when acids and bases are combined together in equal proportions, a process called neutralization.
During neutralization reactions an acid reacts with a base to form a salt and water as the only products.

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3 years ago

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Which unit is not a measurement of volume?<br><br> cm<br> L<br> ml<br> Cm^3

Mademuasel [1]

Centimeters are units of length.

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3 years ago

What purpose did the chemical water serve at the time

elena-14-01-66 [18.8K]

Answer:

At What time?

Explanation:

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3 years ago

If the [H+] in a solution is 1 × 10–1 mol/L, what is the [OH–]? Show your work.

AVprozaik [17]

Hello!

The basic equations to solve this is
pH = -log[H+]
pOH = -log[OH-]
pH + pOH = 14
------------------------------------------------------------------------------------------------------
Find pH

pH = -log(1 * 10^-1)
pH = 1
------------------------------------------------------------------------------------------------------
Find pOH
1 + pOH = 14

pOH = 13
------------------------------------------------------------------------------------------------------
Find OH-
[OH-] = 10^(-pOH)
[OH-] = 1 * 10^-13mo/L

The answer is $[OH-] = 1 * 10^{-13} mol/L$

Hope this helps!

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3 years ago