I think it is aluminum oxide
40g! sorry if i’m wrong!!
Ca(OH)₂ ==> Ca²⁺ + 2 OH<span>-
Ca(OH)</span>₂ is <span>strong Bases</span><span>
</span>Therefore, the [OH-] equals 5 x 10⁻⁴ M. For every Ca(OH)₂ you produce 2 OH⁻<span>.
</span>
pOH = - log[ OH⁻]
pOH = - log [ <span>5 x 10⁻⁴ ]
pOH = 3.30
pH + pOH = 14
pH + 3.30 = 14
pH = 14 - 3.30
pH = 10.7
hope this helps!</span>
Answer :
Option A) 2.00 eV
Explanation : The conversion of J to eV is done with the following formula;

Here, we have the value of particle in terms of Joules which is 3.2 X

So, on substituting we get,

= 3.2 X

X


= 1.99 eV so, it can be rounded off to 2.00 eV.
Copper is an brown-orange color which it's atomic number is 29. With high thermal and electricity conductivity with it's smooth surface.