How many grams of Mg0 are produced from 9.7g of MG
1 answer:
Answer= 16g
Explanation:-
Convert grams to moles:
No. of moles= mass/molar mass (Mr)
So,
9.7/24=0.40 mols
Now, multiply the mols with the coefficients of Mg and MgO in this way:
0.40 x 2/2= 0.4 mols
Finally, multiply 0.4 mols with the molar mass (Mr) of MgO:
0.4 x 40= 16g
16 grams of MgO.
Check the picture to understand>>
Explanation:-
Convert grams to moles:
No. of moles= mass/molar mass (Mr)
So,
9.7/24=0.40 mols
Now, multiply the mols with the coefficients of Mg and MgO in this way:
0.40 x 2/2= 0.4 mols
Finally, multiply 0.4 mols with the molar mass (Mr) of MgO:
0.4 x 40= 16g
16 grams of MgO.
Check the picture to understand>>
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If acetone has a density of 0.7857 the mass in grams of point A is 22.4 g and the volume at point B is 8.32 mL.
Acetone is known as a chemical substance that is usually found in the environment but can also be produced artificially. Acetone is a polar organic product that interacts very well with water molecules, generating dipole-dipole relationships.It is colorless with a distinctive smell and taste, we find it in products known as <u>cleaning and personal care products</u>, but we can also use it as a solvent for substances.
Also in the environment in <u>plants, trees and in volcano emissions or in forest fires</u>, it does not become <em>toxic</em> in low doses but if it is exposed to an individual in high doses it can become <em>fatal</em>.
In the statement we can find that acetone has a density of 0.7857 .
Therefore, we can confirm that if acetone has a density of 0.7857 the mass in grams of point A is 22.4 g and the volume at point B is 8.32 mL.
To learn more about acetone visit: brainly.com/question/13334667?referrer=searchResults
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