You would use the pythagorean theorem. a² +b² =c²
side² +side² = hypotenuse²
So for 1) 8² + 15² = c²
64+225=c²
289=c²
√c² = √289
c = 17
2. 7²+24² =c²
49+576= c²
c²=625
√c²= √625
c = 25
3. 5²+13²=c²
25+169=c²
c² = 194
√c² = √194
c = 13.93
4. 24² + 45² =c²
576 + 2025 =c²
c² = 2601
√c² = √2601
c = 51
5.
Plug each choice into the pythagorean theorem. a² +b² =c²
3²+4² = 5²
9+16= 25
25=25
6²+8²=10²
36+64=100
100=100
16²+63²=65²
256+3969=4225
4225=4225
8²+9²=10²
64+81=100
145=100 Since 145 does not equal 100 it is not a right triangle
If one inch equals 25.4 millimeters, you would have to divide 25.4 by 1/8 which equals to 3.2 (3.175 before rounding). Subtract 3.2 from 25.4 = 22.2 millimeters
Answer:
Now we can find the limits in order to determine outliers like this:
So for this case the left boundary would be 3, if a value is lower than 3 we consider this observation as an outlier
b. 3
Step-by-step explanation:
For this case we have the following summary:
represent the minimum value
represent the first quartile
represent the median
represent the third quartil
represent the maximum
If we use the 1.5 IQR we need to find first the interquartile range defined as:
Now we can find the limits in order to determine outliers like this:
So for this case the left boundary would be 3, if a value is lower than 3 we consider this observation as an outlier
b. 3
Solve for e
d = 1/e + 1/f
Move 1/f to the left side of the = sign
d - 1/f = 1/e
Multiply each side by e
e(d - 1/f) = e(1/e)
e(d - 1/f) = 1
Divide out (d - 1/f)
e(d - 1/f) / (d - 1/f) = 1 / (d - 1/f)
e = 1 / (d - 1/f)
Answer:
Width = 15 feet
Length = 45 feet
Step-by-step explanation:
You need to fence in a rectangular piece of land for your dog to run and play. The length is 3 times the width. If the perimeter is 120 ft, what are the dimensions of your very own dog park?
Perimeter of a rectangle = 2L + 2W
The length is 3 times the width.
L = Length = 3W
W = Width
P = 120 ft
Hence:
120 = 2L + 2W
120 = 2(3W) + 2W
120 = 6W + 2W
120 = 8W
W = 120/8
W = 15 feet
Solving for Length
L = 3W
L = 3 × 15 feet
L = 45 feet
Therefore, the dimensions of your very own dog park is
Width = 15 feet
Length = 45 feet
