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tatuchka [14]
3 years ago
6

A student made a graph to show the chemical equilibrium position of a reaction. The student forgot to label the y-axis of the gr

aph.
What best explains the label that the student should use on the y-axis?

Reaction rate, as the rate of forward and back reaction become equal at equilibrium.

Reaction rate, as the rate of forward reaction increases and rate of backward reaction decreases with time.

Concentration, as the concentration of products decreases and that of reactants increase over time.

Concentration, as the concentrations of reactants and products remain constant after equilibrium is reached.

Chemistry
1 answer:
Kazeer [188]3 years ago
7 0

Answer:

D. concentration, as the concentrations of reactants and products remain unchanged after equilibrium is reached.

Explanation:

I put it for the test and i got right hehe

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The acid dissociation constant Ka of boric acid (H3BO3) is 5.8 times 10^-10. Calculate the pH of a 4.4 M solution of boric acid.
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Answer: The pH of a 4.4 M solution of boric acid is 4.3

Explanation:

H_3BO_3\rightarrow H^+H_2BO_3^-

at t=0  cM              0             0

at eqm c-c\alpha        c\alpha          c\alpha  

So dissociation constant will be:

K_a=\frac{(c\alpha)^{2}}{c-c\alpha}

Give c= 4.4 M and \alpha = ?

K_a=5.8\times 10^{-10}

Putting in the values we get:

5.8\times 10^{-10}=\frac{(4.4\times \alpha)^2}{(4.4-4.4\times \alpha)}

(\alpha)=0.000011

[H^+]=c\times \alpha

[H^+]=4.4\times 0.000011=4.8\times 10^{-5}M

Also pH=-log[H^+]

pH=-log[4.8\times 10^{-5}]=4.3

Thus pH of a 4.4 M H_3BO_3 solution is 4.3

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The condensation response among distinctive molecules of an aldehyde or ketone in a protic solvent which includes water or alcohol constitutes the crossed aldol response. When condensation is among distinctive carbonyl compounds, it's far referred to as crossed aldol condensation.

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