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Triss [41]
3 years ago
9

In a 71.4 g sample of nahco 3 3 ​ , how many grams of sodium are present?

Chemistry
1 answer:
sweet [91]3 years ago
4 0

There are 19.5 g Na in 71.4 g NaHCO₃

Calculate the <em>molecular mass of NaHCO₃</em>.

1 Na = 1 × 22.99 u = 22.99   u

1 H   = 1 × 1.008 u =    1.008 u

1 C   = 1 × 12.01  u =  12.01    u

3 O = 3 × 16.00 u =  <u>48.00  u </u>

               TOTAL =  84.008 u

So, there are 22.99 g of Na in 84.008 g NaHCO₃.

∴ Mass of Na = 71.4 g NaHCO₃ × (22.99 g Na/84.008 g NaHCO₃) = 19.5 g Na

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How many liters of a 2.00 M NaOH solution are needed for a reaction that requires 3.55g of NaOH?
aleksandr82 [10.1K]

Answer:

5 litres of solution are requried

Explanation:

Given that the typical units of

concentration

are

m

o

l

⋅

L

−

1

, to get

concentration

or

amount of moles

or

volume of solution

we just have to take the appropriate product or quotient.

We want

1.0

⋅

m

o

l

N

a

O

H

:

this the product

Volume of solution

×

Concentration

.

So we need the quotient:

Moles of solute

Concentration

=

1.0

⋅

m

o

l

0.2

⋅

m

o

l

⋅

L

−

1

=

5

⋅

L

.

(i.e.

1

1

⋅

L

−

1

=

1

⋅

L

)

Note that we go to such trouble in including the units in these calculations as an extra check on our arithmetic. Sometimes you ask yourself should I divide or should I multiply. Dimensional analysis answers our question. We wanted an answer in

litres

, and we got one. This persuades us that we did the calculation right.

4 0
2 years ago
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vekshin1

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