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Triss [41]
3 years ago
9

In a 71.4 g sample of nahco 3 3 ​ , how many grams of sodium are present?

Chemistry
1 answer:
sweet [91]3 years ago
4 0

There are 19.5 g Na in 71.4 g NaHCO₃

Calculate the <em>molecular mass of NaHCO₃</em>.

1 Na = 1 × 22.99 u = 22.99   u

1 H   = 1 × 1.008 u =    1.008 u

1 C   = 1 × 12.01  u =  12.01    u

3 O = 3 × 16.00 u =  <u>48.00  u </u>

               TOTAL =  84.008 u

So, there are 22.99 g of Na in 84.008 g NaHCO₃.

∴ Mass of Na = 71.4 g NaHCO₃ × (22.99 g Na/84.008 g NaHCO₃) = 19.5 g Na

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The integrated rate law for a second-order reaction is given by:

\frac{1}{[A]t} =   \frac{1}{[A]0} + kt

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<span>                                        = 4.858</span>

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