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3 years ago

In a 71.4 g sample of nahco 3 3 , how many grams of sodium are present?

Chemistry

1 answer:

sweet [91]3 years ago

4 0

There are 19.5 g Na in 71.4 g NaHCO₃

Calculate the molecular mass of NaHCO₃.

1 Na = 1 × 22.99 u = 22.99 u

1 H = 1 × 1.008 u = 1.008 u

1 C = 1 × 12.01 u = 12.01 u

3 O = 3 × 16.00 u = 48.00 u

TOTAL = 84.008 u

So, there are 22.99 g of Na in 84.008 g NaHCO₃.

∴ Mass of Na = 71.4 g NaHCO₃ × (22.99 g Na/84.008 g NaHCO₃) = 19.5 g Na

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What is the molar mass of a gas which occupies 48.7 L at 111oC under 698 torr of pressure and has a mass of 21.5 grams?

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Answer:

Molar mass of the gas = 15.15 g/mol

Explanation:

PV = nRT

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$698\;torr = 698\times0.00131579 = 0.9184\;atm$

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=1.4189 mol

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3 years ago

Convertible bonds are examples of: a. Securities that have characteristics of both debt and equity b. Non-recurring items c. Ass

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Answer:

a. Securities that have characteristics of both debt and equity

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A convertible bond is a debt security that can be converted into a certain number of shares and this can be done during specific times in the life of the bond. According to this, convertible bonds are examples of securities that have characteristics of both debt and equity as they are a type of debt that pays interest but can be turned into shares.

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3 years ago

Calculate the mass of nitric acid required to make a 250mL solution with 2.40 ph

meriva

The mass of nitric acid required to make the given solution is 0.0627 g.

The given parameters:

Volume of the acid, V = 250 mL
pH of the acid, = 2.4

The hydrogen ion (H⁺) concentration of the nitric acid is calculated as follows;

$H^+ = 10^{-pH}\\\\H^+ = 10^{-2.4}\\\\H^+ = 0.00398$

The molarity of the nitric acid is calculated as follows;

$= 0.00398 \ H^+ \times \frac{1 \ M \ HNO_3}{1 \ H^+} \\\\= 0.00398 \ M$

The number of moles of the nitric acid is calculated as follows;

$moles = M\times L\\\\moles = 0.00398\ M \ \times \ \frac{250 \ mL}{1000} \\\\moles = 9.95 \times 10^{-4} \ mol.$

The molar mass of nitric acid is calculated as;

$HNO_3 = (1) \ + (14) \ + (16 \times 3) = 63 \ g/mol$

The mass of the nitric acid contained in the calculated number of moles is calculated as;

$mass = moles\ \times \ molar \ mass\\\\mass = 9.95\times 10^{-4} \ mol. \ \times \ 63 \ g/mol\\\\mass = 0.0627 \ g$

Thus, the mass of nitric acid required to make the given solution is 0.0627 g.

Learn more about molarity of acids here: brainly.com/question/13864682

3 0

2 years ago

In a 71.4 g sample of nahco 3 3 ​ , how many grams of sodium are present?

In a 71.4 g sample of nahco 3 3 , how many grams of sodium are present?