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Masteriza [31]
4 years ago
9

2H2S (g) + 3O2 (g) → 2H2O (g) + 2SO2 (g)

Chemistry
1 answer:
erma4kov [3.2K]4 years ago
3 0
There are three steps to do: 1) convert grams to moles, 2) convert moles to moles and 3) convert moles to grams

1) let's convert the 3.50 grams of H₂S to moles using the molar mass

molar mass H₂S= (2 x 1.01) + 32.0= 34.02 g/mol

3.50 g (1 mol/ 34.02 g)= 0.103 mol H₂S

2) let's convert moles of H₂S to moles of water using the mole-mole ratio from the balanced equation.

0.103 mol H₂S (2 mol H₂O/ 2 mol H₂S)= 0.103 mol H₂O

3) lastly, let's convert moles of water to grams using the molar mass

molar mass of H₂O= (2 x 1.01) + 16.0= 18.02 g/mol

0.103 mol H₂O (18.02 g/ mol)= 1.85 grams of H₂O

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2HgO—>2Hg+O2. I start with 46.8 g HgO. What is my theoretical yield of O2?
jok3333 [9.3K]

Answer:

Theoretical yield = 3.52 g

Percent yield =65.34%

Explanation:

Given data:

Mass of HgO = 46.8 g

Theoretical yield of O₂ = ?

Percent yield of O₂ = ?

Actual yield of O₂ =  2.30 g

Solution:

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2HgO  →   2Hg + O₂

Number of moles of HgO = mass/ molar mass

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Number of moles of HgO = 0.22 mol

Now we will compare the moles of HgO with oxygen.

                         HgO             :             O₂

                             2               :               1

                            0.22           :          1/2×0.22 = 0.11 mol

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Mass of oxygen =  0.11 mol × 32 g/mol

Mass of oxygen = 3.52 g

Percent yield :

Percent yield = actual yield / theoretical yield × 100

Percent yield = 2.30 g/ 3.52 g × 100

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