Question

(c) ammonium carbonate + lead nitrate ? Step-by-step solution Step 1 of 3 v Step 2 of 3 v Step 3 of 3 ^ c) The ions formed in solution are NH4+, Co2, Pb2+ and NO3, combine and form soluble compound NH.NO, so the ions NH,* and NO3 remain in solution, whereas Pb2+ and CO2-form insoluble compound PbCO; Total ionic equation is: 2 NH,+ (aq) + C0,- (aq) + Pb* (aq) + 2 N0,- (aq) → 2 NH,+ (aq) + 2 NO,- (aq) + PbCo () Net ionic equation is: Pb2+ (aq) + CO2-(aq) → PbCo(s)

Answer 1

Answer: The net ionic equation is written below.

Explanation:

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of ammonium carbonate and lead nitrate is given as:

$(NH_4)_2CO_3(aq.)+Pb(NO_3)_2(aq.)\rightarrow PbCO_3(s)+2NH_4NO_3(aq.)$

Ionic form of the above equation follows:

$2NH_4^+(aq.)+CO_3^{2-}(aq.)+Pb^{2+}(aq.)+2NO_3^-(aq.)\rightarrow PbCO_3(s)+2NH_4^+(aq.)+2NO_3^-(aq.)$

As, ammonium and nitrate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$Pb^{2+}(aq.)+CO_3^{2-}(aq.)\rightarrow PbCO_3(s)$

Hence, the net ionic equation is written above.