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3 years ago

There are usually _________ collisions in a motor vehicle crash.

Physics

1 answer:

mel-nik [20]3 years ago

5 0

Answer:

Explanation:

During a crash 3 types of collisions can occur.

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It is a set of measure designed to determine the level of physical fitness?

JulsSmile [24]

<em>The PFT or physical fitness test is a set of measures designed to determine the level of physical fitness.....</em>

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2 years ago

A wire carries a 11.3-mA current along the +x-axis through a magnetic field = (16.2 + 2.4 ĵ) T. If the wire experiences a force

adelina 88 [10]

Answer:

The length of the wire is 579 m

Explanation:

Given;

current on the wire, I = 11.3-mA

magnetic field of the wire, B = (16.2i + 2.4 ĵ) T

Magnitude of force experience by the wire, F = 15.7 N

Magnitude of force experience by current carrying wire at a given a magnetic field strength is calculated as;

F = BILsinθ

Where;

B is magnitude of magnetic field

F is the force on the wire

L is length of the wire

θ is direction of the magnetic field

$B = \sqrt{16.2^2 +2.4^2} = \sqrt{268.2} = 16.377 \ T$

$tan \theta = \frac{2.4}{16.2} \\\\tan \theta = 0.1482\\\\\theta = tan^{-1}(0.1482) \\\\\theta = 8.43^o$

Length of the wire is calculated as;

$L = \frac{F}{BIsin \theta} = \frac{15.7}{16.377*11.3*10^{-3}*sin(8.43)} = 578.9 \ m$

Therefore, the length of the wire is 579 m

5 0

3 years ago

A hiker leaves her camp and walks 3.5 km in a direction of 55° south of west to the lake. after a short rest at the lake, she hi

3241004551 [841]

Let's choose east as positive x-direction and south as positive y-direction. We can resolve the two displacement along these two axes:

- Displacement 1 (3.5 km, $55^{\circ}$ south of west

$d_{1x}=-(3.5 km)( cos 55^{\circ})=-2.01 km$

$d_{1y}=(3.5 km)( sin 55^{\circ})=2.87 km$

- Displacement 2 (2.7 km, $16^{\circ}$ east of south

$d_{2x}=(2.7 km)( sin 16^{\circ})=0.74 km$

$d_{1y}=(2.7 km)( cos 16^{\circ})=2.60 km$

So, the total components on the two directions are

$d_x = -2.01 km+0.74 km=-1.27 km$

$d_y=2.87 km+2.60 km=5.47 km$

And the magnitude of the hiker's resultant displacement is

$d=\sqrt{(1.27 km)^2+(5.47 km)^2}=5.6 km$

8 0

3 years ago

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Answer:

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2 years ago