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2 years ago

5

Find the commission based on total sales of $98,000 and a commission rate of 1.5%.

2 answers:

Nookie1986 [14]2 years ago

8 0

Answer:

$1470

Step-by-step explanation:

98,000 $\rightarrow$ 100%

x $\rightarrow$ 1.5%

$98,000(1.5)=x(100)\\\\x=\frac{98000(1.5)}{100}\\\\x=980*1.5\\\\x=1470$

Lubov Fominskaja [6]2 years ago

6 0

I think the correct answer is $1470

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Which expression can be used to find the volume of the sphere? 10 in.

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Step-by-step explanation:

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2 years ago

Factoring Quadratic Expressions:<br> 5p^2 - p - 18

Dennis_Churaev [7]

$5 p^{2} -p-18$

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2 years ago

Can someone solve this?

ladessa [460]

First question:

Recall that $\cos^2x+\sin^2x=1$ and $\sqrt{x^2}=|x|$ for all $x$ . So

$\sqrt{1-\cos^2x}=\sqrt{\sin^2x}=|\sin x|$

$\sqrt{1-\sin^2x}=\sqrt{\cos^2x}=|\cos x|$

For $0$ , we expect both $\cos x>0$ and $\sin x>0$ (i.e. the sine and cosine of any angle that lies in the first quadrant must be positive). By definition of absolute value, $|x|=x$ if $x>0$ .

So we have

$\dfrac{\sqrt{1-\cos^2x}}{\sin x}+\dfrac{\sqrt{1-\sin^2x}}{\cos x}=\dfrac{\sin x}{\sin x}+\dfrac{\cos x}{\cos x}=1+1=\boxed{2}$

making H the answer.

Second question:

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6 0

3 years ago

Refer to the technology output given to the right that results from measured hemoglobin levels (g/dL) in 100 randomly selected a

charle [14.2K]

Answer:

Step-by-step explanation:

a)

Confidence interval in less than symbol expressed as

$\bar{x} - E < \mu < \bar{x} + E
$

Where $\bar{x}$ is sample mean and $E$ is margin of error.

$13.03 < \mu 13.42
$

b)

The given t interval is $(13.032 , 13.418 )
$

That is $\bar{x} - E = 13.032$ and $\bar{x} + E = 13.418$

Solve these two equation by adding together.

$2 \bar{x} = 13.032 + 13.418
\\\\\bar{x} = 13.225$

Solve this value of \bar{x} in equation $\bar{x} - E = 13.032$ and solve for $E$

$13.225 - E = 13.032
\\\\E = 0.193
$

Best point estimate of $\mu = \bar{x} = 13.225
$

Best point estimate of margin of error = 0.193

c)

Since sample size = 100 which is sufficiently large (Greater than 30) , it is no need to confirm that

sample data appear to be form a population with normal distribution.

8 0

2 years ago