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3 years ago

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The density of liquid mercury is 13.5 g/cm^3. What mass of mercury (in kg) is required to fill a hollow cylinder having an inner

diameter of 2.00 cm to a height of 25.0 cm? *

1 answer:

olya-2409 [2.1K]3 years ago

4 0

Answer: 1.06 kg

Explanation:

Density is defined as the mass contained per unit volume.

$Density=\frac{mass}{Volume}$

Given :

Density of mercury = $13.5g/cm^3$

volume of cylinder = volume of mercury = $\pir^2h$

where r = radius of cylinder = $\frac{diameter}{2}=\frac{2cm}{2}=1cm$

h= height = 25.0 cm

Putting in the values we get:

volume of mercury = $3.14\times 1^2\times 25=78.5cm^3$

$mass=density\times volume=13.5g/cm^3\times 78.5cm^3=1059.75g=1.06kg$ (1kg=1000g)

Thus mass of mercury required to fill a hollow cylinder having an inner diameter of 2.00 cm to a height of 25.0 cm is 1.06 kg.

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