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Artyom0805 [142]
3 years ago
8

What is paraffin wax at room temp

Chemistry
1 answer:
LenaWriter [7]3 years ago
8 0
Paraffin wax at room temperature is solid.
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Hydrogen and Oxygen will have ______ properties after they bond to become water.
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Hydrogen and oxygen will have completely new properties
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You need to determine the mass of an aqueous solution. You determine the mass of your 10.0 mL graduated cylinder to be 23.731 g.
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Answer: 0.86g/mL

Explanation:

Mass of empty cylinder = 23.731g

Mass of cylinder + liquid = 26.414g

Mass of the liquid = 26.414 — 23.731

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Density = 2.683g / 3.12mL

Density = 0.86g/mL

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Identify the family to which the compound (h3c−ch2oh) belongs. identify the family to which the compound (a) belongs. alcohol et
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Each of the organic compounds mentioned has a general formula so that we can identify the classification of a certain substance. The compound CH₃CH₂OH is an alcohol because it follows the general formula R-OH, where R is a hydrocarbon chain. In this case, the hydrocarbon chain is ethane. When a hydroxyl functional group is attached, it becomes an alcohol whose name is ethanol.
5 0
4 years ago
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Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb 1.30 MJ o
Sunny_sXe [5.5K]

Answer:

97 000 g Na

Explanation:

The absortion (or liberation) of energy in form of heat is expressed by:

q=m*Cp*ΔT

The information we have:

q=1.30MJ= 1.30*10^6 J

ΔT = 10.0°C = 10.0 K (ΔT is the same in °C than in K)

Cp=30.8 J/(K mol Na)

If you notice, the Cp in the question is in relation with mol of Na. Before using the q equation, we can find the Cp in relation to the grams of Na.

To do so, we use the molar mass of Na= 22.99g/mol

Cp= \frac{30.8J}{K*mol Na}*\frac{1 mol Na}{22.99 g Na}=1.34\frac{J}{K*g Na}

Now, we are able to solve for m:

m=\frac{1.30*10^6 J}{1.34\frac{J}{K*g Na} *10.0K}=\frac{1.30*10^6J}{13.4\frac{J}{g Na} }  = 9.70*10^4 g Na=97 Kg Na=97 000 g Na

7 0
3 years ago
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Help me please :3 :3 :3 ;3
Alona [7]
I think the answer is C.
8 0
3 years ago
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