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tatiyna
3 years ago
15

During both the vernal equinox and _____________, there is an equal amount of night and day.

Physics
2 answers:
choli [55]3 years ago
5 0
During both the Vernal Equinox and Autumnal equinox, there is an equal amount of night and day
Vernal Equinox marks the beginning of Spring and Autumnal Equinox marks the beginning of Fall

hope this helps
bixtya [17]3 years ago
4 0

Correct answer choice is :


B) Autumnal equinox


Explanation:


An equinox is usually considered as the consequence when the plane of Earth's equator moves through the center of the Sun, which happens twice each year around 20 March and 22–23 September. When the Northern Hemisphere begins to tilt near the sun in spring, the Southern Hemisphere begins to tilt away from the sun, indicating the start of fall. Thus, in the Southern Hemisphere, the March equinox is described the autumnal equinox, and the September equinox is described the vernal equinox.


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What's the momentum (in kg-m/s) of a cannonball with a mass of 21 moving with a velocity of 25 m/s?
lbvjy [14]
P=mv
P=21*25=525 kg*m/s
8 0
3 years ago
A 1 530-kg automobile has a wheel base (the distance between the axles) of 2.70 m. The automobile's center of mass is on the cen
NeTakaya

Answer:

Force on front axle = 6392.85 N

Force on rear axle = 8616.45 N

Explanation:

As we know that the weight of the car is balanced by the normal force on the front wheel and rear wheels

Now we know that

F_1 + F_2 = W

F_1 + F_2 = (1530\times 9.81)

F_1 + F_2 = 15009.3 N

now we know that distance between the axis is 2.70 m and centre of mass is 1.15 m behind front axle

so we can write torque balance about its center of mass

F_1(1.15) = F_2(2.70 - 1.15)

F_1 = 1.35 F_2

now from above equation

F_2 + 1.35F_2 = 15009.3

now we have

F_2 = 6392.85 N

now the other force is given as

F_1 = 8616.45 N

4 0
3 years ago
What is the BEST example of a purebred
ki77a [65]

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8 0
3 years ago
A basketball leaves a player's hands at a height of 2.00 m above the floor. The basket is 3.05 m above the floor. The player lik
shutvik [7]

Answer:(10.69, 11.436)

Explanation:

Given

initial height of ball is 2 m

height of basket is 3.05 m

Launching angle=40^{\circ}

x =12\pm 0.27

y=1.05

equation of trajectory of ball is given by

y=xtan\theta -\frac{gx^2}{2u^2cos^2\theta }

for x=12.27

1.05=12.27\times tan40-\frac{g12.27^2}{2u^2cos^{2}40 }

u=10.69

for x=11.73

1.05=11.73\times tan40-\frac{g11.73^2}{2u^2cos^{2}40 }

u=11.436 m/s

Thus range of speed is (10.69, 11.436)

3 0
3 years ago
How much energy is required to raise the temperature of 50.0 grams of water 10.0 degree C? (Explain yourself answer in joules!)
maria [59]

The amount of energy needed is 2093 J

Explanation:

The amount of energy needed to increase the temperature of a substance by \Delta T is given by the equation

Q=mC\Delta T

where

m is the mass of the substance

C is its specific heat capacity

\Delta T is the increase in temperature

For the water in this problem, we have

m = 50.0 g = 0.050 kg

C=4186 J/g^{\circ}C (specific heat capacity of water)

\Delta T=10.0^{\circ}C

Therefore, the amount of energy needed is

Q=(0.050)(4186)(10)=2093 J

Learn more about specific heat capacity:

brainly.com/question/3032746

brainly.com/question/4759369

#LearnwithBrainly

4 0
3 years ago
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