(a) 5.66 m/s
The flow rate of the water in the pipe is given by
![Q=Av](https://tex.z-dn.net/?f=Q%3DAv)
where
Q is the flow rate
A is the cross-sectional area of the pipe
v is the speed of the water
Here we have
![Q=1.20 m^3/s](https://tex.z-dn.net/?f=Q%3D1.20%20m%5E3%2Fs)
the radius of the pipe is
r = 0.260 m
So the cross-sectional area is
![A=\pi r^2 = \pi (0.260 m)^2=0.212 m^2](https://tex.z-dn.net/?f=A%3D%5Cpi%20r%5E2%20%3D%20%5Cpi%20%280.260%20m%29%5E2%3D0.212%20m%5E2)
So we can re-arrange the equation to find the speed of the water:
![v=\frac{Q}{A}=\frac{1.20 m^3/s}{0.212 m^2}=5.66 m/s](https://tex.z-dn.net/?f=v%3D%5Cfrac%7BQ%7D%7BA%7D%3D%5Cfrac%7B1.20%20m%5E3%2Fs%7D%7B0.212%20m%5E2%7D%3D5.66%20m%2Fs)
(b) 0.326 m
The flow rate along the pipe is conserved, so we can write:
![Q_1 = Q_2\\A_1 v_1 = A_2 v_2](https://tex.z-dn.net/?f=Q_1%20%3D%20Q_2%5C%5CA_1%20v_1%20%3D%20A_2%20v_2)
where we have
![A_1 = 0.212 m^2\\v_1 = 5.66 m/s\\v_2 = 3.60 m/s](https://tex.z-dn.net/?f=A_1%20%3D%200.212%20m%5E2%5C%5Cv_1%20%3D%205.66%20m%2Fs%5C%5Cv_2%20%3D%203.60%20m%2Fs)
and where
is the cross-sectional area of the pipe at the second point.
Solving for A2,
![A_2 = \frac{A_1 v_1}{v_2}=\frac{(0.212 m^2)(5.66 m/s)}{3.60 m/s}=0.333 m^2](https://tex.z-dn.net/?f=A_2%20%3D%20%5Cfrac%7BA_1%20v_1%7D%7Bv_2%7D%3D%5Cfrac%7B%280.212%20m%5E2%29%285.66%20m%2Fs%29%7D%7B3.60%20m%2Fs%7D%3D0.333%20m%5E2)
And finally we can find the radius of the pipe at that point:
![A_2 = \pi r_2^2\\r_2 = \sqrt{\frac{A_2}{\pi}}=\sqrt{\frac{0.333 m^2}{\pi}}=0.326 m](https://tex.z-dn.net/?f=A_2%20%3D%20%5Cpi%20r_2%5E2%5C%5Cr_2%20%3D%20%5Csqrt%7B%5Cfrac%7BA_2%7D%7B%5Cpi%7D%7D%3D%5Csqrt%7B%5Cfrac%7B0.333%20m%5E2%7D%7B%5Cpi%7D%7D%3D0.326%20m)
Answer:
distance and time
Explanation: the farther you go and how much time it will take you
Answer:
Explanation:
They have the same kinetic energy
Autotrophs are organisms that can make its own food by synthesizing organic nutrients from inorganic materials. Three types include: photoautotrophs, chemoautotrophs, and plants.