Answer:
The magnitude of gravitational force between two masses is
.
Explanation:
Given that,
Mass of first lead ball, 
Mass of the other lead ball, 
The center of a large ball is separated by 0.057 m from the center of a small ball, r = 0.057 m
We need to find the magnitude of the gravitational force between the masses. It is given by the formula of the gravitational force. It is given by :

So, the magnitude of gravitational force between two masses is
. Hence, this is the required solution.
Answer:


Explanation:
if

and g=9.81 m/s2=32.16 ft/s2
and
W=m*g
we can just replace de mass and gravity and we have


Answer:
28,800m/p second
Explanation:
Calculate the distance per second so, 400m/50 s= 8m/p second now knowing the speed/hour and knowing an hour has 3,600 seconds,multiply it by 8 then you will get 28,800m/p second, or 28.8km/h
Answer:
i3 =11.014A
i5 = 3.15A
Explanation:
Here according to k'chofs first law
i1 =i2 + i3
i3 = i4 + i5
For determine the i1 you have to consider the resultant resistor of the system
4 , 1 and 3 resistors are in pararel
Then, Resultant is
1/4 + 1/1 + 1/3 = 1/ R
R = 12/19
For get total we have to add another remaining 3 resistor because of serious
Then Resultant is = 12/19 + 3
= 69/19
Then using V = IR
40 =i3* 69/19
i3 = 11.014 A
Other 3 resistors are parrarel because of this voltage of those resistors are same.
Then i inversely propotional to its resistor
Then ,
i5 * 2 = (i3-i5)*4/5
i 5 = 3.15 A
To solve the problem it is necessary to take into account the concepts related to beat frequency, i.e., The number of those wobbles per second.
The equation that describes the beat frequency is

For our given case we have that the frequency of the instrument is 440Hz and the Beat frequency is 5Hz therefore,
A) The frequency of the violin would be given by




B) <em>The violinist must loosen the string.</em> As the tightening increases the frequency, thereby increasing the number of beats from 5 to 6, i. e, on thightening the string, the frequency further increases as high frequency will be produced by short trings.