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Anestetic [448]
3 years ago
11

Select the correct answer.

Physics
1 answer:
Svetllana [295]3 years ago
6 0

Answer:

Both are electromagnetic waves

Explanation:

Both microwaves and light waves form a part of the electromagnetic spectrum. Electromagnetic waves are produced as a result of oscillating magnetic and electric fields. when arranged in order of frequencies and wavelengths they form the electromagnetic spectrum.

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Which form of energy does a battery-powered flashlight receive as an input?
BaLLatris [955]

Answer:

A

Explanation:

Energy is stored inside the batteries. Thus it is chemical potential energy

7 0
3 years ago
A new company is making security cameras. These security cameras will be different than other security cameras because instead o
babunello [35]

Answer:

b

Explanation:

4 0
2 years ago
PLEASE HELP!
lana66690 [7]

Answer:

x = 4.32 [m]

Explanation:

We must divide this problem into three parts, in the first part we must use Newton's second law which tells us that the force is equal to the product of mass by acceleration.

∑F = m*a

where:

F = force = 700 [N]

m = mass = 2030 [kg]

a = acceleration [m/s²]

Now replacing:

F=m*a\\700=2030*a\\a = 0.344[m/s^{2}]

Then we can determine the final speed using the principle of conservation of momentum and amount of movement.

(m_{1}*v_{1})+Imp_{1-2}=(m_{1}*v_{2})

where:

m₁ = mass of the car = 2030 [kg]

v₁ = velocity at the initial moment = 0 (the car starts from rest)

Imp₁₋₂ = The impulse or momentum (force by the time)

v₂ = final velocity after the impulse [m/s]

(2030*0) + (700*5)=(2030*v_{2})\\3500 = 2030*v_{2}\\v_{2}=1.72[m/s]

Now using the following equation of kinematics, we can determine the distance traveled.

v_{2}^{2} =v_{1}^{2}+2*a*x

where:

v₂ = final velocity = 1.72 [m/s]

v₁ = initial velocity = 0

a = acceleration = 0.344 [m/s²]

x = distance [m]

1.72^{2}=0^{2} +(2*0.344*x) \\2.97 = 0.688*x\\x = 4.32 [m]

8 0
3 years ago
SOMEONE HELP QUICK! (question in the picture)
kondor19780726 [428]
1) 4.8
2) 5.6
3)0.8
.............………
8 0
3 years ago
At time t=0t=0 a proton is a distance of 0.360 mm from a very large insulating sheet of charge and is moving parallel to the she
insens350 [35]

Answer:

1.34 * 10^{3}m/s

Explanation:

Parameters given:

distance of the proton form the insulating sheet = 0.360mm

speed of the proton, v_{x} = 990m/s

Surface charge density, σ = 2.34 x 10^{-9} C/m^{2}

We need to calculate the speed at time, t = 7.0 * 10^{-8}s.

We know that the proton is moving parallel to the sheet, hence, we can say it is moving in the x direction, with a speed v_{x} on the axis.

The electric force acting on the proton moves in the y direction, so this means it is moving with velocity v_{y} in the y axis.

Hence, the resultant velocity of the proton is given by:

v = \sqrt{v_{x} ^{2} + v_{y} ^{2}}

v_{x} = 990m/s from the question. We need to find v_{y} and then the resultant velocity v.

Electric field is given in terms of surface charge density, σ as:

E = σ/ε0

where ε0 = permittivity of free space

=> E = \frac{2.34 * 10^{-9} } {2 * 8.85418782 * 10^{-12} }

E =  132 N/C

Electric Force, F is given in terms of Electric field:

F = eE

where e = electronic charge

=> F = ma = eE

∴ a = eE/m

where

a = acceleration of the proton

m = mass of proton

a = \frac{1.60 * 10^{-19} * 132}{1.672 * 10^{-27} }

a = 1.3 * 10^{10} m/s^{2}

Therefore, at time, t = 7.0 * 10^{-8}, we can use one of the equations of linear motion to find the velocity in the y axis:

a = \frac{v_{y} - v_{0}}{t} \\\\=> v_{y} = v_{0} + at

v_{y} = 0 + (1.3 * 10^{10} * 7.0 * 10^{-8})

v_{y} = 910 m/s

∴ v = \sqrt{v_{x} ^{2} + v_{y} ^{2}}

v = \sqrt{990^{2} + 910^{2} }

v = \sqrt{1808200}

v = 1344.69 m/s = 1.34 * 10^{3}m/s

8 0
4 years ago
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