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Alona [7]
2 years ago
11

On the periodic table, what is used to determine the order of elements? (Use your own words? Help please!!!

Chemistry
2 answers:
Bezzdna [24]2 years ago
5 0

in periodic table, elements are arranged according to atomic number; beginning with Hydrogen at 1, Helium at 2 n so on. atomic number represents the no. of proton or electron each neutral element has.


Angelina_Jolie [31]2 years ago
4 0

Elements are listed in order of increasing atomic number from the left to the right.

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The heat of vaporization of acetic acid is . Calculate the change in entropy when of acetic acid condenses at .
Umnica [9.8K]

The question is incomplete, the complete question is;

The heat of vaporization ΔHv of acetic acid HCH3CO2 is 41.0 /kJmol. Calculate the change in entropy ΔS when 954.g of acetic acid condenses at 118.1°C. Be sure your answer contains a unit symbol. Round your answer to 3 significant digits.

Answer:

-1.67 JK-1

Explanation:

Since Heat of vaporization of acetic acid = 41.0 kJ/mol

Therefore:

Heat of condensation of acetic acid = -41.0 kJ/mol

Mass of acetic acid = 954 g

Temperature of condensation = 118.1 °C or 391.1 K

Number of moles of acetic acid = 954 g/60g/mol = 15.9 moles

Heat evolved during condensation = 15.9 moles *  -41.0 kJ/mol = -651.9 KJ

Entropy change (ΔS) = Heat evolved/ Temperature = -651.9 KJ/391.1 K

Entropy change (ΔS) = -1.67 JK-1

8 0
2 years ago
URGENT!!!! Please respond in less than 5 mins hurry!!!!?!!?!!??!?
AleksAgata [21]

Answer:

1. A

2. B

Explanation:

1. Most of the answers don't make that much sense, so using process of elimination I resulted in this answer. I recommend you also try to check with others.

2. This question also was pretty confusing but when using process of elimination I resulted in either A or B. To me B makes more sense.

5 0
3 years ago
PLEASE ANSWER
k0ka [10]

Answer: The awnser is A

Explanation:

8 0
3 years ago
Read 2 more answers
Kemmi Major does some experimental work on the combustion of sucrose: C12H22O11(s) 12 O2(g) → 12 CO2(g) 11 H2O(g) She burns a 0.
Pavlova-9 [17]

Answer: 5.81\times 10^6J/mol

Explanation:

Heat of combustion is the amount of heat released when 1 mole of the compound is completely burnt in the presence of oxygen.

C_{12}H_{22}O_{11}(s)+12O_2\rightarrow 12CO_2(g)+11H_2O(g)

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}=\frac{0.05392g}{342g/mol}=1.577\times 10^{-4}moles

Thus 1.577\times 10^{-4}moles of sucrose releases =  916.6 J of heat

1 mole of sucrose releases =\frac{916.6}{1.577\times 10^{-4}}\times 1=5.81\times 10^6J of heat

Thus ∆H value for the combustion reaction is 5.81\times 10^6J/mol

6 0
3 years ago
Which VIIA element doesn't have stable isotopes in nature?
Stolb23 [73]
Hello there.

<span>Which VIIA element doesn't have stable isotopes in nature?

</span>Db. At
8 0
3 years ago
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