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kirill115 [55]
3 years ago
8

A mineral contains only a metal, M, and sulfur. If analysis indicates that a 4.3 g sample of the mineral contains 1.56 g of M, w

hat mass of M (g) is contained in 396 g of the mineral? Enter your answer in decimal format with two decimal places and no units.
Chemistry
1 answer:
oee [108]3 years ago
4 0

Answer: 143.66 grams of M (g) is contained in 396 g of the mineral

Explanation:

Given : mineral contains metal M and sulphur

Mass of mineral = 4.3 g

Mass of metal M in mineral = 1.56 g

Thus if 4.3 gram of mineral contains metal = 1.56 g

Using unitary method for solving this :

1 g of mineral contains metal =\frac{1.56}{4.3}\times 1=0.36

396 g of mineral contains metal =0.36\times 396=143.66 g

Thus 143.66 grams of M (g) is contained in 396 g of the mineral

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the question you are looking for is

A compound containing only sulfur and nitrogen is 69.6% S by mass; the molar mass is 184 g/mol. What are the empirical and molecular formulas of the compound?

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1 year ago
How many moles of Co2 are produced when 0.2 moles of sodium carbonate reacts with excess HCl
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From the initial amount given of sodium carbonate and the relation of the substances from the balanced reaction, we calculate the moles of carbon dioxide as follows:

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3 years ago
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