A mineral contains only a metal, M, and sulfur. If analysis indicates that a 4.3 g sample of the mineral contains 1.56 g of M, w
1 answer:
Answer: 143.66 grams of M (g) is contained in 396 g of the mineral
Explanation:
Given : mineral contains metal M and sulphur
Mass of mineral = 4.3 g
Mass of metal M in mineral = 1.56 g
Thus if 4.3 gram of mineral contains metal = 1.56 g
Using unitary method for solving this :
1 g of mineral contains metal =
396 g of mineral contains metal =
Thus 143.66 grams of M (g) is contained in 396 g of the mineral
You might be interested in
Acid-base neutralization reaction is defined as reaction of acid with base to form corresponding salt and water. Strong acid and base completely neutralize each other.
(a) The acid base neutralization reaction is as follows:
From the above balanced chemical reaction, 1 mol of NaOH completely reacts with 1 mol of HCl. The mass of NaOH is given 4.85 g, convert this into number of moles as follows:
Molar mass of NaOH is 39.997 g/mol, thus,
Thus, 0.121 mol of NaOH reacts with same amount of HCl and number of moles of HCl will be 0.121 mol.
Since. molar mass of HCl is 36.46 g/mol, thus, mass can be calculated as follows:
Therefore, 4.421 g of HCl completely reacts with 4.85 g of NaCl.
(b) The acid base neutralization reaction is as follows:
From the above balanced chemical reaction, 1 mol of completely reacts with 2 mol of
. The mass of
is given 4.85 g, convert this into number of moles as follows:
Molar mass of is 74.093 g/mol, thus,
Thus, 0.06545 mol of reacts with
of
Since. molar mass of is 63.01 g/mol, thus, mass can be calculated as follows:
Therefore, 8.25 g of completely reacts with 4.85 g of
.
(c) The acid base neutralization reaction is as follows:
From the above balanced chemical reaction, 2 mol of KOH completely reacts with 1 mol of . The mass of KOH is given 4.85 g, convert this into number of moles as follows:
Molar mass of KOH is 56.1056 g/mol, thus,
Thus, 0.0864 mol of KOH reacts with of
Since. molar mass of is 98.079 g/mol, thus, mass can be calculated as follows:
Therefore, 4.24 g of KOH completely reacts with 4.85 g of .