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kirill115 [55]
3 years ago
8

A mineral contains only a metal, M, and sulfur. If analysis indicates that a 4.3 g sample of the mineral contains 1.56 g of M, w

hat mass of M (g) is contained in 396 g of the mineral? Enter your answer in decimal format with two decimal places and no units.
Chemistry
1 answer:
oee [108]3 years ago
4 0

Answer: 143.66 grams of M (g) is contained in 396 g of the mineral

Explanation:

Given : mineral contains metal M and sulphur

Mass of mineral = 4.3 g

Mass of metal M in mineral = 1.56 g

Thus if 4.3 gram of mineral contains metal = 1.56 g

Using unitary method for solving this :

1 g of mineral contains metal =\frac{1.56}{4.3}\times 1=0.36

396 g of mineral contains metal =0.36\times 396=143.66 g

Thus 143.66 grams of M (g) is contained in 396 g of the mineral

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Answer:

A. 3 Significant Figures

B. 6 Significant Figures

C. 2 Significant Figures

D. 4 Significant Figures

E. 4 Significant Figures

F. 5 Significant Figures

Explanation:

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What are the two most common elements found in the universe?​
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That would be hydrogen and helium! :)

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Lead(II) nitrate is added slowly to a solution that is 0.0800 M in Cl− ions. Calculate the concentration of Pb2+ ions (in mol /
barxatty [35]

Answer:

[Pb^{2+}]=3.9 \times 10^{-2}M

this is the concentration required to initiate precipitation

Explanation:

PbCl_2  ⇄ Pb^{2+}+2Cl^-

Precipitation starts when ionic product is greater than solubility product.

Ip>Ksp

Precipitation starts only when solution is supersaturated because solution become supersaturated then it does not stay in this form and precipitation starts itself only solution become saturated.

This usually happens when two solutions containing separate sources of cation and anion are mixed together and here also we are mixing lead (||)nitrate solution(source of lead(||)) into the Cl- solution.

Ip=[Pb^{2}][2Cl^-]^2=Ksp

Ksp=2.4\times 10^{-4}

lets solubility=S

[Pb^{2+}] = S

[Cl^-]=2S

Ksp=[Pb^{2+}]\times [Cl^-]^2

Ksp=S \times (2S)^2

Ksp=4S^3

S=\sqrt[3]{\frac{Ksp}{4} }

S=3.9\times 10^{-2}

[Pb^{2+}]=3.9 \times 10^{-2}M this is the concentration required to initiate precipitation

4 0
3 years ago
The naturally occurring radioactive decay series that begins with 23592U stops with formation of the stable 20782Pb nucleus. The
dsp73

Answer: There are 7 alpha-particle emissions and 4 beta-particle emissions involved in this series

Explanation:

Alpha Decay: In this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. The mass number is reduced by 4 units and atomic number is reduced by 2 units.

Beta Decay : It is a type of decay process, in which a proton gets converted to neutron and an electron. This is also known as -decay. In this the mass number remains same but the atomic number is increased by 1.

In radioactive decay the sum of atomic number or mass number of reactants must be equal to the sum of atomic number or mass number of products .

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