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abruzzese [7]
3 years ago
14

Beakers A, B, C, and D shown below each contain a different aqueous

Chemistry
1 answer:
Nataly_w [17]3 years ago
4 0

Answer: a n b

Explanation:

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What kind of air pressure would you find in Bridgeport, Connecticut?
klasskru [66]

Answer:

Warm

Explanation: because it would be less hot air population

3 0
4 years ago
Suppose the mass spectrum of a hypothetical monatomic element x contains a signal at mass number 13 and another of identical hei
ArbitrLikvidat [17]
For this case, Only 1 isotope would be present, i.e. the principal element with mass M=13 and then one isotope at mass M+2. <span>We are assuming that the principal element is the one that is the lowest mass - by definition, an isotope is one where there are additional neutrons - hence the mass increases, but the proton count is the same. 


</span>
4 0
3 years ago
A 10.0 cm3 sample of copper has a mass of 89.6 g. What is the density of copper
natali 33 [55]

Answer:

<h2>Density = 8.96 g/cm³</h2>

Explanation:

The density of a substance can be found by using the formula

Density =  \frac{mass}{volume}

From the question

mass of copper = 89.6 g

volume = 10 cm³

Substitute the values into the above formula and solve

That's

Density =  \frac{89.6}{10}

We have the final answer as

<h3>Density = 8.96 g/cm³</h3>

Hope this helps you

7 0
4 years ago
The equilibrium constant for the reaction
FinnZ [79.3K]

Answer: The concentrations of Cl_2 at equilibrium is 0.023 M

Explanation:

Moles of  Cl_2 = \frac{\text {given mass}}{\text {Molar mass}}=\frac{10g}{71g/mol}=0.14mol

Volume of solution = 1 L

Initial concentration of Cl_2 = \frac{0.14mol}{1L}=0.14M

The given balanced equilibrium reaction is,

                            COCl_2(g)\rightleftharpoons CO(g)+Cl_2(g)

Initial conc.           0.14 M           0 M       0M    

At eqm. conc.     (0.14-x) M        (x) M        (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[CO]\times [Cl_2]}{[COCl_2]}

Now put all the given values in this expression, we get :

4.63\times 10^{-3}=\frac{x)^2}{(0.14-x)}

By solving the term 'x', we get :

x = 0.023 M

Thus, the concentrations of Cl_2 at equilibrium is 0.023 M

7 0
3 years ago
Please Help!!! 25 POINTS!!!
son4ous [18]

Answer:

1. independent

2. question

3. same

4. true

5 0
3 years ago
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