A student checked the conductivity of 2 different solids and the results are listed in the table below explain why the students
got these results in terms of principles of chemical bonding your explanation should include a discussion of the specific particles present is fake particles present in each substance and how the behavior of these particles is related to the conductivity of the solid?
1 answer:
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NaOH is an example of an ionic crystal.
Option a
<h3><u>Explanation:</u></h3>Sodium Hydroxide is a "white solid ionic compound" consisting of sodium cations Na+ and hydroxide anions . If we look at the crystal structure of NaOH, we can see that it has the combinations of ionic and covalent bonds. The bond that is shared between Oxygen ( O ) and Hydrogen ( H ) is the covalent bond.
The Sodium ( Na ) is bonded with an "ionic bond to the hydroxide part of the compound". NaOH is an ionic solid because it is formed by the combinations of metal and non-metal. When the crystal of NaOH is dissolved in water it dissociates into Na+ ions (which is ionic in nature) and ions which bonds ionically to the other compounds.
Answer:
a) The mechanism of the reaction is the Elimination Bimolecular or E2.
b) Steps for the mechanism of this reaction is given as follows,
c) Reaction rate = K[Organic compound][].
Explanation:
a) The mechanism of the reaction is the Elimination Bimolecular or E2.
c) This is an E2 reaction, so it depends on the concentration of both substrate and reactant. If we increase the concentration of , the reaction rate will be increased.
Reaction rate = K[Organic compound][].
b) Steps for the mechanism of this reaction is given as follows,
