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n200080 [17]
2 years ago
9

A student checked the conductivity of 2 different solids and the results are listed in the table below explain why the students

got these results in terms of principles of chemical bonding your explanation should include a discussion of the specific particles present is fake particles present in each substance and how the behavior of these particles is related to the conductivity of the solid?

Chemistry
1 answer:
lbvjy [14]2 years ago
7 0

Solid copper conducts electricity because of the presence of free electrons. There are no free electrons in CuCl2(g) hence it does not conduct electricity.

Metals are known as conductors of electricity because, in the metallic bond, free electrons are attracted to metal cations by electrostatic forces. These free electrons explains the conductivity of solid metals.

However, when these metals form compounds, ions are present. These ions only conduct electricity in the liquid or aqueous states when the ions are free to move about. In the solid or gaseous state, these ions are not free hence, CuCl2(g) does not conduct electricity.

Learn more: brainly.com/question/11527546

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Refer to the two formulas for xylose.
Ludmilka [50]

Answer:

A is the molecular formula for xylose because shows the actual number of atoms in the compound: Formula B is the empirical formula for xylose because it shows the smallest whole-number ratio for the different atoms in the compound: Formula A is the molecular formula for xylose because shows the arrangement of atoms in the compound: Formula B is the structurab formula for xylose because it shows the smallest whole-number ratio for the different atoms in the compound: Formula A is the empirical formula for xylose because it shows the actual number of atoms in the compound: Formula B is the molecular formula for xylose because it shows the smallest whole-number ratio for the different atoms in the compound: Formula A is the structural formula for xylose because it shows the arrangement of atoms in the compound: Formula B is the empirical formula for xylose because it shows the smallest whole-number ratio for the different atoms in the compound.

5 0
2 years ago
Homogeneous series of n-propyl bromide?
goldenfox [79]

The homologous series ( not homogeneous series ) of n-propyl bromide is C3H7Br. It is also known as 1-Bromopropane

n-propyl bromide or 1-bromopropane, is a solvent that is used in cleaning metals, vapor degreasing and also for dry cleaning.

<h3>What is Homologous series?</h3>

Homologous series is a family of organic compound which follows a regular structural pattern and in which successive members differs from one another by a molecular formula of CH2

Below are some of their characteristics:

  • The general formula of all compounds in the series is the same.
  • They have the same functional group.
  • Their physical properties such as melting point, boiling point, density, generally show a gradual change with increase of molecular formula in the series.

Learn more about homogeneous series:

brainly.com/question/14008526

3 0
2 years ago
Read 2 more answers
An object weighting 9.6 grams is placed in a graduated cylinder displacing the volume from 10.0mL to 13.2 mL
grigory [225]

The volume of object is 3.2 ml

<h3>Explanation:</h3>

Given:

Mass of the object = M = 9.6 g

Initial volume of liquid: V_1 = 10.0\ ml

Final volume of liquid after displacement: V_2 = 13.2\ ml

Total volume of the displaced object inside a graduating cylinder will be given as difference between the final volume and initial volume of the expanding object.

V = V_2-V_1 = 13.2 -1 0.0 = 3.2\ ml

V = 3.2 ml

3 0
3 years ago
ou will prepare 250-mL of this solution using a 30% (m/v) NaOH stock solution. How many mL of the NaOH stock solution will you n
ArbitrLikvidat [17]

Answer:

\boxed{\text{3.3 mL}}

Explanation:

You must convert 30 % (m/v) to a molar concentration.

Assume 1 L of solution.

1. Mass of NaOH

\text{Mass of NaOH} = \text{1000 mL solution } \times \dfrac{\text{30 g NaOH}}{\text{100 mL solution}} = \text{300 g NaOH}

2. Moles of NaOH  

\text{Moles of NaOH} = \text{300 g NaOH} \times \dfrac{\text{1 mol NaOH}}{\text{40.00 g NaOH}} = \text{7.50 mol NaOH}

3. Molar concentration of NaOH

c= \dfrac{\text{moles}}{\text{litres}} = \dfrac{\text{7.50 mol}}{\text{1 L}} = \text{7.50 mol/L}

4. Volume of NaOH

Now that you know the concentration, you can use the dilution formula .

c_{1}V_{1} = c_{2}V_{2}

to calculate the volume of stock solution.

Data:

c₁ = 7.50 mol·L⁻¹; V₁ = ?

c₂ = 0.1   mol·L⁻¹; V₂ = 250 mL

Calculations:

(a) Convert millilitres to litres

V = \text{250 mL} \times \dfrac{ \text{1 L}}{\text{1000 mL}} = \text{0.250 L}

(b) Calculate the volume  of dilute solution

\begin{array}{rcl}7.50V_{1} & = & 0.1 \times 0.250\\7.50V_{1} &= & 0.0250\\V_{1} & = & \text{0.0033 L}\\& = & \textbf{3.3 mL}\\\end{array}

\text{You will need $\boxed{\textbf{3.3 mL}}$ of the stock solution.}

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Suppose a skier is standing still at the top of a hill.what kind of energy does the skier have
barxatty [35]
In response to your question, the kind of energy the skier has is called potential energy.
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