Answer:
6.6 atm
Explanation:
Using the general gas law
P₁V₁/T₁ = P₂V₂/T₂
Let P₂ be the new pressure
So, P₂ = P₁V₁T₂/V₂T₁
Since V₂ = 2V₁ , P₁ = 12 atm and T₁ = 273 + t where t = temperature in Celsius
T₂ = 273 + 2t (since its Celsius temperature doubles).
Substituting these values into the equation for P₂, we have
P₂ = P₁V₁(273 + 2t)/2V₁(273 + t)
P₂ = 12(273 + 2t)/[2(273 + t)]
P₂ = 6(273 + 2t)/(273 + t)]
assume t = 30 °C on a comfortable spring day
P₂ = 6(273 + 2(30))/(273 + 30)]
P₂ = 6(273 + 60))/(273 + 30)]
P₂ = 6(333))/(303)]
P₂ = 6.6 atm
Work=applied Force x distance
= 1275 x 26
=33150 Joules
The final velocity of the airplane is 7.2 m/s
Explanation:
The motion of the airplane is a uniformly accelerated motion, (constant acceleration), therefore we can use the suvat equation
v = u + at
where
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
In this problem, we have
u = 6 m/s is the initial velocity
is the acceleration
t = 4 s is the time elapsed
Substituting the values, we find the velocity after 4 seconds:
Learn more about accelerated motion:
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