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kap26 [50]
3 years ago
13

How do you know when electric current is flowing in a lightbulb circuit?

Physics
1 answer:
daser333 [38]3 years ago
7 0
The direction of an electric current is by convention the direction in which a positive charge would move. Thus, the current in the external circuit is directed away from the positive terminal and toward the negative terminal of the battery. Electrons would actually move through the wires in the opposite direction.
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Which two options describes behaviors of particles that are related to the chemical properties of the materials
jarptica [38.1K]

Answer:

The two correct answers are B.) reacting quickly with water, and D.) forming bonds with other atoms.

Explanation:

3 0
3 years ago
Identify the charge(s) with increasing electric potential energy.
kap26 [50]
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4 0
3 years ago
An arrow is moving at 35 m/s and travels for 5 seconds. how far did the arrow travel?
pashok25 [27]
The answer is 175 meters
8 0
3 years ago
A single slit, which is 0.050 mm wide, is illuminated by light of 550 nm wavelength. What is the angular separation between the
likoan [24]

Answer:

The separation between the first two minima on either side is 0.63 degrees.

Explanation:

A diffraction experiment consists on passing monochromatic light trough a small single slit, at some distance a light diffraction pattern is projected on a screen. The diffraction pattern consists on intercalated dark and bright fringes that are symmetric respect the center of the screen, the angular positions of the dark fringes θn can be find using the equation:

a\sin \theta_n=n\lambda

with a the width of the slit, n the number of the minimum and λ the wavelength of the incident light. We should find the position of the n=1 and n=2 minima above the central maximum because symmetry the angular positions of n=-1 and n=-2 that are the angular position of the minima below the central maximum, then:

for the first minimum

a\sin \theta_1=(1)\lambda

solving for θ1:

\theta_1=\arcsin (\frac{\lambda}{a})=\arcsin (\frac{550\times10^{-9}}{0.05\times10^{-3}})

\theta_1=0.63 degrees

for the second minimum:

a\sin \theta_2=(2)\lambda

\theta_2=\arcsin (\frac{2\lambda}{a})=\arcsin (\frac{2*550\times10^{-9}}{0.05\times10^{-3}})

\theta_2=1.26 degrees

So, the angular separation between them is the rest:

\Delta \theta =1.26-0.63

\Delta \theta=0.63

4 0
3 years ago
Spring A has a spring constant of 100 N/m and spring B has a spring constant of 200 N/m, and both have the same displacement of
igor_vitrenko [27]

Answer:

Explanation:

Given

Spring constant of spring A is k_A=100\ N/m

Spring constant of spring B is k_B=200\ N/m

If displacement in both the springs is x=0.2\ m

Potential Energy stored in the spring is given by

U=\frac{1}{2}kx^2

where k=spring constant

x=compression or extension

U_A=\frac{1}{2}\times 100\times (0.2)^2----1

U_B=\frac{1}{2}\times 200\times (0.2)^2----2

Divide 1 and 2

\frac{U_B}{U_A}=\frac{200}{100}=2

U_A=\frac{U_B}{2}

So Potential Energy Stored in Spring A is half of Spring B

7 0
3 years ago
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