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kap26 [50]
3 years ago
13

How do you know when electric current is flowing in a lightbulb circuit?

Physics
1 answer:
daser333 [38]3 years ago
7 0
The direction of an electric current is by convention the direction in which a positive charge would move. Thus, the current in the external circuit is directed away from the positive terminal and toward the negative terminal of the battery. Electrons would actually move through the wires in the opposite direction.
You might be interested in
A chemical reaction takes place in which energy is absorbed. Arrange the characteristics of the reaction in order from start to
myrzilka [38]

Let’s create a diagram that shows the chemical reaction absorb energy. Take a look at the diagram I created that is attached to this answer.


Now, the start of the graph line is pretty flat and low leveled. This is the start, which is the reactants. The beginning of a chemical reaction that absorbs energy will almost always start with reactants. I labeled this this “Start: Reactants” and colored the text light green so you can easily detect the part I’m talking about.


Moving on, we see there’s a light blue arrow pointing from the the near bottom to the top curve of the graph line. This is the where the activation energy is rising. Activation energy is the difference between the reactants and products. When the graph line begins to cure, this is when the transition state is beginning. I labeled the transition state, “Transition State” and colored the text a light orange. I colored the line a light blue and also labeled it “Activation Energy” and colored the text light blue as well. I hope it’s easy enough for you to follow along. :)


Next we see that the graph line dips and then goes flat, but it doesn’t go low leveled. It says fairly higher than where it started. This is the end product. I labeled this “End: Product” and colored the text light purple so you can easily detect it.


Okay, now that that’s clear, let’s go ahead and fill in the first blank. According to the diagram we see that the start should be a reactant, and since the graph line starts out pretty low. So, this means that the first tile should be “Low energy of reactants."


Now the second tile should definitely be “Transition State.” This is because the second part in the diagram is transition state. Again, this is mainly where the activation energy is starting to rise.


As for the last and final tile, we should chose “High energy of products.” This is because the diagram is left off on a high leveled part at the end of the graph line.


So, when you place the tiles they should look something like this.


Low energy of reactants

↓

Transition state

↓

High energy of products



- Marlon Nunez

8 0
4 years ago
Read 2 more answers
A 240-volt, 2-amp motor is connected to a three-wire, 120/240-volt system. Connected between the black wire and neutral are four
pantera1 [17]

Answer:

(i)The current flow in black wire = 9.67 A (ii) The current low in the red wire is 9.68 A (iii) The current flow in neutral wire is  15.36 A (iv) when 240 volt were disconnected current  in black wire is 7.68 A (v) when 240 volt were disconnected current in red wire is 7.68 A (vi) 15.36 A (vii) 6.34 (viii) 9.68 A (ix) 12.02 A

Explanation:

Solution

The current drawn by one amp is

I =P/V

I =200/120

I= 1.67 A

(i) The current flow in the black wire  is

IBK = 4 * 1.67 A + 1A + 2A

IBK = 9.67 A

(ii) Current flow in the red wire is

IRD = 3 * 1.67 A + 1.67 A + 1A + 2A

= 8.68A + 1 A = 9.68 A

Note: Kindly find an attached copy of part of the solution to the given question above.

6 0
3 years ago
___________ are considered to be the building blocks of rocks
marysya [2.9K]

Explanation:

minerals

false

pyrite is an ore of gold

false

coal

7 0
4 years ago
Read 2 more answers
You have been offered an admission to a senior high school to persue a programme you like. Write a letter to the headteacher of
Anna [14]

Answer:

Find the letter below.

Explanation:

                                                                                1237 Richmond Avenue,

                                                                                Houston, Texas,

                                                                                U.S.A.

                                                                                3rd May, 2021.

The Principal,

Carnegie Vanguard High School,

Houston, Texas,

U.S.A.

Dear Sir,

           APPRECIATION FOR THE ADMISSION OFFER IN YOUR SCHOOL

          I humbly write this letter to express my sincere appreciation for the offer of admission in your highly esteemed institution of learning. The admission letter states that I was admitted to pursue a programme in Computer Science and this is a source of great delight for me. The opportunity is a unique one because I stand a great chance of acquiring deeper knowledge of programming software that will prove invaluable to me in my future career.  

         Over the years, I have been particularly thrilled with all the inventions that have been made possible with information technology and programming of many useful software. These inventions have made life a lot easier, hence my interest in getting the required knowledge that will enable me to contribute my quota to the society.

         This programme will also afford me the opportunity to relate with seasoned professionals in the field of Information Technology. When in contact with these professionals, I hope to ask them several questions on programming, the technicalities involved in it, and what is obtainable in the real-world scenario. Armed with these pieces of information, I believe that the programme will shape me to be an excellent professional that will be useful to the society.

         Once again, thank you for this very special opportunity. I hope to fully maximize the privilege.

Yours Sincerely,

Jessica Liam.

                                                                               

       

5 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
Luden [163]

Answer:

The ball will be attracted to the negatively charged plate. It'll touch and pick up some electrons from the plate so that the ball becomes negatively charged. Immediately the ball is repelled by the negative plate and is attracted to the positive plate. The ball gives up electrons to the positive plate so that it is positively charged and suddenly attracts to the negative plate again, flies over to it and picks up enough electrons to be repulsed by negative plate and again to the positive plate and that continues.

8 0
3 years ago
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