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alekssr [168]
3 years ago
14

Simplify. (4w + 3) – 2w + 7 2w + 10 2w - 10 6w + 10 6w - 10

Mathematics
1 answer:
7nadin3 [17]3 years ago
3 0
Hey there,

2w+10 would be the best choice here.
Sorry if I'm wrong, good luck!

:)
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If a diameter of a circle has endpoints (-3,5) and<br> (5, 7), then the center of the circle is
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Answer:

(1 , 6)

Step-by-step explanation:

the center of the circle is the midpoint of the diameter

Which is the point of coordinates:

(\frac{-3+5}{2} ,\frac{5+7}{2} )

Then the center is the point :

(1 , 6)

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The value in Canadian dollars of the money in Merl's bank account goes down because it takes .14 more Yuan to make 1 Canadian dollar.
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A bank paid 2.3% interest on a money market account. What is 2.3% written as a decimal
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What is the x-intercept and the y-intercept for x+2y=8
Ierofanga [76]
To find the x-intercept, you need to set y equal to zero(think about this on a  graph!)
This will become:
x + 2(0) = 8
If we remove the unnecessary zero:
x = 8
That's the x intercept, which can be expressed as the point (8,0).

To find the y-intercept, you need to set x equal to zero(again, think about that on a graph!)
This becomes:
0 + 2y = 8
Remove the unnecessary 0:
2y = 8
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y = 4
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Hope this helped! :)
~Chrys
8 0
3 years ago
A recent survey showed that in a sample of 100 elementary school teachers, 15 were single. In a sample of 180 high school teache
trapecia [35]

Answer:

By using hypothesis test at α = 0.01, we cannot conclude that the proportion of high school teachers who were single greater than the proportion of elementary teachers who were single

Step-by-step explanation:

let p1  be the proportion of elementary teachers who were single

let p2 be the proportion of high school teachers who were single

Then, the null and alternative hypotheses are:

H_{0}: p2=p1

H_{a}: p2>p1

We need to calculate the test statistic of the sample proportion for elementary teachers who were single.

It can be calculated as follows:

\frac{p(s)-p}{\sqrt{\frac{p*(1-p)}{N} } } where

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  • p is the proportion of elementary teachers who were single (\frac{15}{100} =0.15)
  • N is the sample size (180)

Using the numbers, we get

\frac{0.2-0.15}{\sqrt{\frac{0.15*0.85}{180} } } ≈ 1.88

Using z-table, corresponding  P-Value is ≈0.03

Since 0.03>0.01 we fail to reject the null hypothesis. (The result is not significant at α = 0.01)

8 0
3 years ago
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