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yuradex [85]
3 years ago
10

How do changes in light wavelengths support the big bang theory?

Physics
2 answers:
jek_recluse [69]3 years ago
5 0

Lights from other galaxies shifts toward the red end of the spectrum, which shows that the galaxies are moving away from the earth.  <em>(A)</em>

likoan [24]3 years ago
5 0

Answer: A

Explanation:

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A ball is thrown straight upward. When it has reached the highest point in its motion, and is momentarily stopped, its accelerat
Damm [24]
Increased .....................
7 0
3 years ago
A plane wave with a wavelength of 500 nm is incident normally ona single slit with a width of 5.0 × 10–6 m.Consider waves that r
kaheart [24]

To solve this exercise it is necessary to use the concepts related to Difference in Phase.

The Difference in phase is given by

\Phi = \frac{2\pi \delta}{\lambda}

Where

\delta = Horizontal distance between two points

\lambda = Wavelength

From our values we have,

\lambda = 500nm = 5*10^{-6}m

\theta = 1\°

The horizontal distance between this two points would be given for

\delta = dsin\theta

Therefore using the equation we have

\Phi = \frac{2\pi \delta}{\lambda}

\Phi = \frac{2\pi(dsin\theta)}{\lambda}

\Phi = \frac{2\pi(5*!0^{-6}sin(1))}{500*10^{-9}}

\Phi= 1.096 rad \approx = 1.1 rad

Therefore the correct answer is C.

6 0
3 years ago
A 100 mH inductor whose windings have a resistance of 6.0 Ω is connected across a 12 Vbattery having an internal resistance of 3
Alexus [3.1K]

Answer:

The store energy in the inductor is 0.088 J

Explanation:

Given that,

Inductor = 100 mH

Resistance = 6.0 Ω

Voltage = 12 V

Internal resistance = 3.0 Ω

We need to calculate the current

Using ohm's law

V = IR

I=\dfrac{V}{R+r}

Put the value into the formula

I=\dfrac{12}{6.0+3.0}

I=1.33\ A

We need to calculate the store energy in the inductor

U=\dfrac{1}{2}LI^2

U=\dfrac{1}{2}\times100\times10^{-3}\times(1.33)^2

U=0.088\ J

Hence, The store energy in the inductor is 0.088 J

7 0
3 years ago
Different between current and electrons?
BlackZzzverrR [31]

Answer:

Simply,

<u>electrons</u> are "PARTICLES" orbiting the atoms, where, <u>current</u><u> </u>is the FLOW of some (free-to-move-around) electrons in a wire...

3 0
3 years ago
a star has a distance of 30 parsecs and a apparent magnitude of 3 --what would its absolute magnitude be?
Alborosie

The absolute magnitude of the star would be +5.

8 0
1 year ago
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