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VashaNatasha [74]
1 year ago
15

the general circulation of the atmosphere represents the actual air flow around the world and not just an average. group of answ

er choices true false
Physics
1 answer:
solmaris [256]1 year ago
8 0

False The atmosphere's general circulation actually depicts the air flow around the world, not just an average.

<h3>What is global circulation in general?</h3>

The necessary transportation of heat from tropical to polar latitudes is performed by a system of winds that is known as the global circulation. Hadley cell, Ferrel cell, and Polar cell are the three cells in each hemisphere where air flows across the whole depth of the troposphere.

<h3>What type of nighttime air circulation pattern is typically linked with coastlines?</h3>

The wind turns around and blows out over the ocean at night because the land cools more quickly than the water. This is known as a land breeze. Additionally, the sun's rays have an impact on large-scale atmospheric circulation.

To know more about circulation of the atmosphere visit:-

brainly.com/question/788466

#SPJ4

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Students can take the aspire test in ninth and grade
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<em>The answer is </em>Ninth <em>and </em>Tenth <em>grade so the answer would be</em> B

<em>I hope this helps you </em>


3 0
3 years ago
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United States citizens have many ways to participate in national life. The most common form of participation is?
Travka [436]

Answer:

You would have to give better explanation on subject.

Explanation:

3 0
2 years ago
Identify and explain which ball most likely had the greatest speed.
deff fn [24]
Y, bc the height of the bounce back is higher than x
4 0
2 years ago
A spring with a spring constant of 120 J/m2 is fixed to a wall, free to oscillate. On the other end, a ball with a mass of 1500
Neporo4naja [7]

Answer:

A. 4.47 m/s

Explanation:

As the ball oscillates, it mechanical energy, aka the total kinetic and elastics energy stays the same. For the ball to be at maximum speed, its elastic energy i 0 and vice versa. When the ball is at rest, its kinetic energy is 0 and its elastic energy is at maximum at 50 cm, or 0.5 m

1500 g = 1.5 kg

E_e = E_k

kx^2/2 = mv^2/2

120*0.5^2/2 = 1.5*v^2/2

15 = 0.75v^2

v^2 = 15 / 0.75 = 20

v = \sqrt{20} = 4.47 m/s

5 0
3 years ago
A 500 kg dragster accelerates from rest to a final speed of 100 m/s in 400 m (about a quarter of a mile) and encounters an avera
Fantom [35]
In order to accelerate the dragster at a speed v_f = 100 m/s, its engine must do a work equal to the increase in kinetic energy of the dragster. Since it starts from rest, the initial kinetic energy is zero, so the work done by the engine to accelerate the dragster to 100 m/s is
W= K_f - K_i = K_f =  \frac{1}{2}mv_f^2=2.5 \cdot 10^6 J

however, we must take into account also the fact that there is a frictional force doing work against the dragster, and the work done by the frictional force is:
W_f = F_f d = -(1200 N)(400 m)= -4.8 \cdot 10^5 J
and the sign is negative because the frictional force acts against the direction of motion of the dragster.

This means that the total work done by the dragster engine is equal to the work done to accelerate the dragster plus the energy lost because of the frictional force, which is -W_f:
W_t = W + (-W_f)=2.5 \cdot 10^6 J+4.8 \cdot 10^5 J=2.98 \cdot 10^6 J

So, the power delivered by the engine is the total work divided by the time, t=7.30 s:
P= \frac{W}{t}= \frac{2.98 \cdot 10^6 J}{7.30 s}=4.08 \cdot 10^6 W

And since 1 horsepower is equal to 746 W, we can rewrite the power as
P=4.08 \cdot 10^6 W \cdot  \frac{1 hp}{746 W} =547 hp



3 0
3 years ago
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