Answer:
V = 0.39 m/s
Explanation:
Given that,
Mass of hockey puck, m = 0.2 kg
Mass of goalie = 40 kg
Speed of hockey puck, v = 80 m/s
We need to find the speed with which the goalie slide on the slide. Let V be the speed. Using the conservation of momentum as follows :
So, the required speed is 0.39 m/s.
Answer:
about 4 km
Explanation:
15 minutes is a quarter of an hour, so you divide 16km by 4 to get your answer
Answer:
Explanation:
A )
At the bottom of the circle , the potential energy of the stopper is converted into kinetic energy
1/2 m V² = mg x 2r + 1/2 mv²
m is mass of stopper , V is velocity at the bottom , r is radius of the circular path which is length of the string , v is velocity at the top
1/2 V² = g x 2r + 1/2 v²
V² = g x 4r + v²
V² = 9.8 x 4 + 8²
V² = 103.2
V = 10.16 m/s
B )
If T be the tension at the top
Net downward force
= mg + T . This force provides centripetal force for the circular motion
mg +T = mv² / r
T = mv²/r -mg
= m ( v²/r - g )
= .005 ( 8²/1 -g )
= .005 x 54.2
= .27 N .
C ) At the bottom
Net force = T - mg , T is tension at the bottom , V is velocity at bottom
T-mg = mV²/r
T = m ( V²/r +g )
= .005 ( 10.16²/1 +9.8)
= .005 x 113
= .56 N .
The far right.
Fg is gravity which always acts down and since we assume the floor is flat the normal, Fn, acts opposite gravity, so straight up.
But you’re probably wondering about the pushing force, Fp, and the friction force, Ff. For the Fp, consider where the applied force is coming from. The head of the broom is on the floor and the man’s arms, where he’s applying the force from, is above and to the left, so when the man pushes the broom the force is down and to the right. The broom my not be moving down, but the applied force is still in that direction. And Ff always acts against motion so since the broom moves to the right, the friction is to the left.
