A skier (down a straight course) is able to enter the starting gate with a speed of 1 m/sec and the average acceleration down th
e hill was 3 m/s2. If
the skier covers the course in 10 sec, how fast was he moving at the bottom of the course?
O31 m
O 13 m/s
O-29 m/s
O 31 m/s
the skier covers the course in 10 sec, how fast was he moving at the bottom of the course?
O31 m
O 13 m/s
O-29 m/s
O 31 m/s
1 answer:
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Answer:
the direction of rate of change of the momentum is against the motion of the body, that is, downward.
The applied force is also against the direction of motion of the body, downward.
Explanation:
The change in the momentum of a body, if the mass of the body is constant, is given by the following formula:
p: momentum
m: mass
: change in the velocity
The sign of the change in the velocity determines the direction of rate of change. Then you have:
v2: final velocity = 35m/s
v1: initial velocity = 40m/s
Hence, the direction of rate of change of the momentum is against the motion of the body, that is, downward.
The applied force is also against the direction of motion of the body, downward.