A skier (down a straight course) is able to enter the starting gate with a speed of 1 m/sec and the average acceleration down th
e hill was 3 m/s2. If
the skier covers the course in 10 sec, how fast was he moving at the bottom of the course?
O31 m
O 13 m/s
O-29 m/s
O 31 m/s
the skier covers the course in 10 sec, how fast was he moving at the bottom of the course?
O31 m
O 13 m/s
O-29 m/s
O 31 m/s
1 answer:
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Horizontal speed = 24.0 m/s
height of the cliff = 51.0 m
For the initial vertical speed will are considering the vertical component. Therefore,
Since the student fires the canonical ball at the maximum height of 51 m, the initial vertical velocity will be zero. This means
let's find how long the ball remained in the air.
Finally, let's find the how far from the base of the building the ball landed(horizontal distance)
Answer:
<h2>11.91 m/s</h2>Explanation:
The velocity of an object can be found by using the formula
d is the distance
t is the time taken
From the question we have
We have the final answer as
<h3>11.91 m/s</h3>Hope this helps you