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PilotLPTM [1.2K]
4 years ago
12

Which is the standard equation for a circle centered at the origin with radius

Mathematics
1 answer:
sergeinik [125]4 years ago
6 0

Answer:

The equation would be x^2 + y^2 = r^2

Step-by-step explanation:

This is the base form of any circle. In this case, you would need the value of the radius to finish the equation.

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What is the value of 1/3 x^2 + 5.2y when x = 3 and y = 2?<br><br> PLZ HELP!!!
olasank [31]
The first step in solving this is to substitute x with 3 and y with 2, so that
\frac{1}{3} x^{2} +5.2y
becomes
\frac{1}{3}  (3)^{2} +5.2(2)
Then simply solve using the order of operations.
First exponents (there are no parentheses)
\frac{1}{3} 9 +5.2(2)
Then multiply and divide
3+10.4
And finally add and subtract
13.4
Therefore the value <span>of 1/3 x^2 + 5.2y when x=3 and y=2 is 13.4</span>
6 0
3 years ago
Slope : - 9/7 point : ( -7,4 )
dolphi86 [110]
To form an equation with the given information, we use the formula :

y = mx + b, m being the slope and b being the y-intercept.

Since it is given that the slope is -9/7, we substitute m with -9/7.

y = -9/7x + b

To find b, we will substitute the known coordinates into the equation :
At point (-7 , 4), x = -7, y = 4

4 = -9/7 (-7) + b
4  = 9 + b
b = 4 - 9
b = -5

Now we know that b = -5, we will substitute b = -5 into the equation that we found earlier, y = -9/7 x + b :

y = - 9/7x - 5

To make it more readable, we can multiply the equation by 7:
7y = -9x - 5
7y + 9x + 5 = 0

-----------------------------------------------------------
Answer : 7y + 9x + 5 = 0
-----------------------------------------------------------
7 0
4 years ago
Write the equation of a Line that is perpendicular to y=5/2x+3 and passes
koban [17]

Answer:

Step-by-step explanation:

Slope of perpendicular lines = -1

y = 5/2x + 3

m_{1}=\frac{5}{2}\\\\m_{1}*m_{2}=-1\\\\

        m_{2}= -1 ÷ m_{1}

               = -1*\frac{2}{5}=\frac{-2}{5}

(-3 , -5)

Equation of the required line: y - y₁ = m(x -x₁)

                                                y - [5] = \frac{-2}{5}(x - [-3])\\

                                               y+5=\frac{-2}{5}x + 3*\frac{-2}{5}\\\\y+5=\frac{-2}{5}x-\frac{6}{5}\\\\   y =\frac{-2}{5}x-\frac{6}{5}-5\\\\   y = \frac{-2}{5}x-\frac{6}{5}-\frac{5*5}{1*5}\\\\ y = \frac{-2}{5}x-\frac{6}{5}-\frac{25}{5}\\\\\\ y=\frac{-2}{5}x-\frac{31}{5}

5 0
4 years ago
Is ZERO a natural number?
Artist 52 [7]
Yes if you whant look in google
4 0
3 years ago
Find the slope of the line on the graph. Reduce all fractional answers to lowest terms.
Vera_Pavlovna [14]

Answer:

1

Explanation:

Slope formula:

y₂ - y₁ / x₂ - x₁

2 - (-2) / 2 - (-2)

2 + 2 / 2 + 2

4 / 4

= 1

6 0
3 years ago
Read 2 more answers
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