A pathogen that has nutrients absorbed from its environment is called fungus. Fungus is a eukaryotic microorganism that is a heterotroph and acquire its food by absorbing dissolved molecules, typically by secreting digestive enzymes into their environment
The nitrogenous bases Adenine form two hydrogen bonds with thymine and the cytosine form three hydrogen bonds with the guanine. Simply, A combines with T and G combines with the C. It is often called as a complementary base pairing because of each base pair bonds only with its specific complementary base partner in a DNA molecule.
Answer:
0.153
Explanation:
We know the up-thrust on the fish, U = weight of water displaced = weight of fish + weight of air in air sacs.
So ρVg = ρ'V'g + ρ'V"g where ρ = density of water = 1 g/cm³, V = volume of water displaced, g = acceleration due to gravity, ρ'= density of fish = 1.18 g/cm³, V' = initial volume of fish, ρ"= density of air = 0.0012 g/cm³ and V" = volume of expanded air sac.
ρVg = ρ'V'g + ρ"V"g
ρV = ρ'V'g + ρ"V"
Its new body volume = volume of water displaced, V = V' + V"
ρ(V' + V") = ρ'V' + ρ"V"
ρV' + ρV" = ρ'V' + ρ"V"
ρV' - ρ"V' = ρ'V" - ρV"
(ρ - ρ")V' = (ρ' - ρ)V"
V'/V" = (ρ - ρ")/(ρ' - ρ)
= (1 g/cm³ - 0.0012 g/cm³)/(1.18 g/cm³ - 1 g/cm³)
= (0.9988 g/cm³ ÷ 0.18 g/cm³)
V'/V" = 5.55
Since V = V' + V"
V' = V - V"
(V - V")/V" = 5.55
V/V" - V"/V" = 5.55
V/V" - 1 = 5.55
V/V" = 5.55 + 1
V/V" = 6.55
V"/V = 1/6.55
V"/V = 0.153
So, the fish must inflate its air sacs to 0.153 of its expanded body volume
I believe the answer is c
When a muscle contract, it will become shorten. To kick a ball, there are many muscles used for moving the leg. Muscle from the thigh will move the lower leg and the power of kick comes from this muscle group. The muscle in the lower leg will control the feet and determine whether kick using the front or side of the feet.
Since the muscle in one side contract, the opposite muscle in the muscle pair will be flexed. The muscle in flex condition will be lengthened.
