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Maurinko [17]
3 years ago
9

Calculate the mechanical advantage of a pulley system if only 10 lb is required to lift a 500 lb block.

Physics
1 answer:
mote1985 [20]3 years ago
3 0

Answer:

50 is the answer.. the formula is load/effort

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Two parallel-plate capacitors have the same dimensions, but the space between the plates is filled with air in capacitor 1 and w
Aleks [24]

Explanation:

The capacitance in two parallel-plate capacitors is:

C=\frac{K\epsilon_oA}{d}

For air, we have K_1=1

For plastic, we have K_2=2.25

Hence:

C_1=\frac{K_1\epsilon_oA}{d_1}=\frac{\epsilon_oA}{d_1}\\C_2=\frac{K_2\epsilon_oA}{d_2}=2.25(\frac{\epsilon_oA}{d_2})

a) Recall that the potential difference between the plates is the same (V_1=V_2=V). The electric field is given by:

E_1=\frac{V_1}{d_1}=\frac{V}{d_1}\\E_2=\frac{V_2}{d_2}=\frac{V}{d_1}

The potential difference is defined as:

V_1=\frac{Q_1}{C_1}=V\\V_2=\frac{Q_2}{C_2}=V

Replacing:

E_1=\frac{Q_1}{C_1d_1}\\E_2=\frac{Q_1}{C_1d_2}\\\\E_1d_1=\frac{Q_1}{C_1}\\E_2d_2=\frac{Q_1}{C_1}\\E_1d_1=E_2d_2\\\frac{E_1}{E_2}=\frac{d_2}{d_1}

b) The energy is defined as:

U=\frac{1}{2}CV^2

So:

U_1=\frac{1}{2}C_1V_1^2=\frac{1}{2}C_1V^2\\U_2=\frac{1}{2}C_2V_2^2=\frac{1}{2}C_2V^2\\U_1=\frac{1}{2}\frac{\epsilon_oA}{d_1}V^2\\U_2=\frac{1}{2}\frac{2.25\epsilon_oA}{d_2}V^2\\\frac{0.88U_2d_2}{\epsilon_oA}=V^2\\\frac{2U_1d_1}{\epsilon_oA}=V^2\\\frac{0.88U_2d_2}{\epsilon_oA}=\frac{2U_1d_1}{\epsilon_oA}\\\frac{U_1}{U_2}=0.44\frac{d_2}{d_1}

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3 years ago
16g 2g/cm3 what is the Volume
lord [1]

Answer:

V =  1.25E-7 cubic meter

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3 years ago
How much charge must pass by a point in a wire in 1.5 s for the current inb the wire to be 2.0 A?
skelet666 [1.2K]

Answer:

3 Coulombs

Explanation:

Q = Current x time

Q = 2.0 x 1.5

Q = 3 Coulombs

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Fair enough ! Where's the figure ?
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