The combustion of ethane is expressed in the balanced reaction C2H6 + 3.5O2= 2CO2 + 3 H2O. Given the mass of oxygen gas, we get the moles of ethane needed by converting this mass to mole (dividing my 32 g/mol), then multiply by 1/3.5 (stioch ratio) and the molar mass of ethane (30 g/mol). The answer is 16.69 grams ethane.
Hydroboration-oxidation is a reaction which follow anti markonikov orientation.
The stereochemistry of hydroboration-oxidation follows syn-adition being a stereospecific reaction. That means that boron and hydrogen are added from the same side. Then, when the oxidation occurs, the boron is replaced by an hydroxyl having the same geometric position.
your answer will be :
B. <u>Na has a lower</u> <u>electronegativity than H</u>
because Na belongs to alkali metals which are least electronegative (most electro positive) but hydrogen is a non metal, it has higher electronegativity as compared to metals like Sodium (Na).
Answer:
Double Covalent
Explanation:
When two of the same element combine it will always be a covalent bond between them and since sulfur has two lone electrons it will make a double bond between the two to have a full octect
Answer:
6.82 moles of Fe2O3
Explanation:
Step 1:
Determination of the number of mole of in 450g of CO2.
This is illustrated below:
Molar Mass of CO2 = 12 + (2x16) = 44g/mol
Mass of CO2 = 450g
Number of mole of CO2 =.?
Number of mole = Mass/Molar Mass
Number of mole of CO2 = 450/44 = 10.23 moles
Step 2:
Determination of the number of mole of Fe2O3 needed for the reaction. This is illustrated below:
2Fe2O3 + 3C—> 4Fe + 3CO2
From the balanced equation above,
2 moles of Fe2O3 reacted to produce 3 moles of CO2.
Therefore, Xmol of Fe2O3 will react to produce 10.23 moles of CO2 i.e
Xmol of Fe2O3 = (2x10.23)/3
Xmol of Fe2O3 = 6.82 moles
Therefore, 6.82 moles of Fe2O3 is required.
