Answer:
According to Coulomb’s law, the Ca and Se ions have 4 times the attractive force (2+ × 2-) than that of the K and Br ions (1+ × 1-).
Explanation:
From Coulomb's law, the attractive force between calcium and selenium ions is four times the attractive force between potassium and bromide ions.
This has something to do with size and magnitude of charge. Calcium ions and selenide ions are smaller and both carry greater charge magnitude than potassium and bromide ions. This paves way for greater electrostatic attraction between them when the distance of the charges apart is minimal. Hence a greater lattice energy.
Answer:
<em>That's </em><em>because</em><em> </em><em>in </em><em>water</em><em> </em><em>NaF </em><em>will </em><em>dissolve</em><em> </em><em>to </em><em>produce </em><em>Na</em><em>+</em><em>,</em><em>the </em><em>conjugate </em><em>base </em><em>of </em><em>a </em><em>strong</em><em> </em><em>acid </em><em>which</em><em> </em><em>will </em><em>not </em><em>react </em><em>with </em><em>water.</em><em>h</em><em>o</em><em>w</em><em>e</em><em>v</em><em>e</em><em>r</em><em> </em><em>F- </em><em>will </em><em>behave </em><em>like </em><em>a </em><em>bronsted </em><em>base,</em><em> </em><em>and </em><em>accept</em><em> </em><em>a </em><em>proton </em><em>from </em><em>water.</em><em>t</em><em>h</em><em>i</em><em>s</em><em> </em><em>is </em><em>called </em><em>hydrolysis</em><em> </em><em>reaction,</em><em> because</em><em> </em><em>a </em><em>molecule</em><em> </em><em>of </em><em>water </em><em>is </em><em>broken </em><em>up.</em>
<em>a </em><em>conjugate</em><em> base</em><em> </em><em>is </em><em>what </em><em>I </em><em>leftover </em><em>after </em><em>an </em><em>acid </em><em>loses </em><em>a </em><em>hydrogen</em><em> </em><em>ion.</em>
<em>I </em><em>hope</em><em> this</em><em> helps</em>
Answer:
So sorry if I was wrong but I think it's B. Because from the source states,
https://socratic.org/questions/which-group-on-the-periodic-table-is-the-least-reactive-why
"The least reactive elements are those who have a full outermost valence shell ie they have 8 electrons in the outer shell so elements such as helium, neon, radon or the transition elements."
Answer:
The answer to your question is P = 0.18 atm
Explanation:
Data
mass of O₂ = 0.29 g
Volume = 2.3 l
Pressure = ?
Temperature = 9°C
constant of ideal gases = 0.082 atm l/mol°K
Process
1.- Convert the mass of O₂ to moles
16 g of O₂ -------------------- 1 mol
0.29 g of O₂ ---------------- x
x = (0.29 x 1)/16
x = 0.29/16
x = 0.018 moles
2.- Convert the temperature to °K
Temperature = 9 + 273 = 282°K
3.- Use the ideal gas law ro find the answer
PV = nRT
-Solve for P
P = nRT/V
-Substitution
P = (0.018 x 0.082 x 282) / 2.3
-Simplification
P = 0.416/2.3
-Result
P = 0.18 atm
Answer: 1/12
1/4 divided by 3/1
KCF:Keep the first fraction, Change the sign to muplication, Flip the second fraction.
1/4* 31
1*1=1
4*3=12
1/12
