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nata0808 [166]
3 years ago
10

What is the mass of 1.84 mol NaCl? Give your answer to the correct number of significant figures. (Molar mass of NaCl = 58.44 g/

mol)
Chemistry
2 answers:
eduard3 years ago
8 0

yes 108 is correct thank u

Roman55 [17]3 years ago
3 1
Mol =  \frac{mass}{molecular weight}
Rearranged to give grams = molecular weight  * mol
grams = 1.84 * 58.44 = 107.53 grams
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In a chemical equation, a subscript tells one how many atoms or molecules of a reactant or a product take part in a reaction.

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What is density? How do you find it?
Assoli18 [71]

Density is the measure of a mass per unit volume of a material substance

density= Mass/volume

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5 0
3 years ago
16. A solution is made by dissolving 25 g of NaCl in enough water to make 1.0 L of solution. Assume the density of the solution
nata0808 [166]

Answer:

The molarity will be "0.43 M" and molality will be "0.43 m".

Explanation:

Given that:

mass of NaCl,

= 25 g

Volume of solution,

= 1 L

Density of solution,

= 1 gm/cm³

Now,

The weight of solvent will be:

= Volume\times density

= 1\times 1

= 1 \ kg

The mole of NaCl will be:

= \frac{mass}{Molar \ mass}

= \frac{25}{58.44}

= 0.43

hence,

The molarity will be:

= \frac{number \ of \ mole}{Volume \ of \ solution}

= \frac{0.43}{1}

= 0.43 \ M

The molality will be:

= \frac{mole \ of \ solute}{Weight \ of \ solvent}

= \frac{0.43}{1}

= 0.43 \ m

4 0
3 years ago
What is the density of a gas at 242.5K and 0.7311atm. The molar mass of this gas is 70.90g/mol
Pie

Answer:

0.384g/l

Explanation: the density version of the ideal gas law is pm=drt

in which p= pressure, m=molar mass,d=, density, r= to a constant which is 0.08206, and t=temperature so just input the values

PM=DRT. so to find d the formula would be D=RT\PM

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4 0
3 years ago
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Montano1993 [528]
Q = mC∆T 

<span>where: </span>
<span>q = heat </span>
<span>m = mass of substance = 35.0 grams </span>
<span>C = 0.385 J/g*C </span>
<span>∆T = change in temperature = 65C - 20C = 45C </span>

<span>q = (35.0 g)*(0.385 J/g*C)*(45C) = 606 J </span>
3 0
3 years ago
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