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3 years ago

A gas has a volume of 2,280 ml. at 30.0C and 808 mm. pressure. Calculate its volume at standard temperature and pressure.

Chemistry

1 answer:

White raven [17]3 years ago

7 0

Explanation:

Which statement best evaluates the effectiveness of the conclusion

paragraph?

Thesis Statement: My future job must include human interaction, a

nontraditional workspace, and teamwork.

Main Points:

1. Work with people

2. Work in a nontraditional workspace

3. Work in a place where coworkers share ideas

Conclusion: In the end, my future job will be one that allows me to

collaborate with my coworkers in dynamic and nontraditional

workspaces. If I am forced to sit behind a desk I will be extremely bored. Furthermore, I will be less productive if I am forced to work alone without the chance to discuss ideas with my coworkers. So the next time an adult asks me what I want to do when

I grow up, I will tell them a job without a desk, in an office full of

people. That's my dream job!

A. The conclusion is effective because it presents interesting information not addressed in the body paragraphs.

B. The conclusion is ineffective because it does not restate the thesis in a new way.

C. The conclusion is effective because it restates the thesis, summarizes the main points, and includes a satisfying close.

D. The conclusion is ineffective because it fails to leave the reader with a thought-provoking question.Which statement best evaluates the effectiveness of the conclusion

paragraph?

Thesis Statement: My future job must include human interaction, a

nontraditional workspace, and teamwork.

Main Points:

1. Work with people

2. Work in a nontraditional workspace

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A student places a 100.0°C piece of metal that weighs 85.5 g into 122 mL of 16.0°C water. If the final temperature is 20.2°C, wh

Musya8 [376]

Answer:

The specific heat of the metal is 0.314 J/g°C

Explanation:

Step 1: data given

Temperature of the piece of metal = 100.0 °C

Mass of the metal = 85.5 grams

Volume of water = 122 mL = 122 grams

Temperature of water = 16.0 °C

The final temperature of water = 20.2 °C

The specific heat of water = 4.184 J/g°C

Step 2: Calculate the specific heat of metal

Heat gained= heat lost

Qgained = - Qlost

Qwater = -Qmetal

Q = m*c* ΔT

m(metal)*c(metal)*ΔT(metal) = -m(water)*c(water)*ΔT(water)

⇒m(metal) = mass of metal = 85.5 grams

⇒c(metal) = the specific heat of metal = TO BE DETERMINED

⇒ΔT(metal) = the change of temperature of metal = T2 - T1 = 20.2 - 100 °C = -79.8 °C

⇒m(water) = the mass of water = 122 grams

⇒c(water) = the specific heat of water = 4.184 J/g°C

⇒ΔT(water) = the change of temperature of metal = T2 - T1 = 20.2 - 16.0 °C = 4.2 °C

85.5 *c(metal) * -79.8 = -122 * 4.184 * 4.2

c(metal) * (-6822.9) = -2143.9

c(metal) = 0.314 J/g°C

The specific heat of the metal is 0.314 J/g°C

7 0

3 years ago

Given the equation Ca + H2O --> Ca(OH)2 + H2 how many grams of calcium will react completely with 10.0 grams of water? *

Yuki888 [10]

Answer: 11.0 g of calcium will react with 10.0 grams of water.

Explanation:

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}$

moles of $H_2O$

$\text{Number of moles}=\frac{10.0g}{18g/mol}=0.55moles$

The balanced chemical equation is:

$Ca+2H_2O\rightarrow Ca(OH)_2+H_2$

According to stoichiometry :

2 moles of $H_2O$ require = 1 mole of $Ca$

Thus 0.55 moles of $H_2O$ require= $\frac{1}{2}\times 0.55=0.275moles$ of $Ca$

Mass of $Ca=moles\times {\text {Molar mass}}=0.275moles\times 40g/mol=11g$

Thus 11.0 g of calcium will react with 10.0 grams of water.

3 0

3 years ago

Particles of light are known as

Mashcka [7]

HEY DEAR..

The particles of light known as photon.

HOPE ITS HELPFULL

6 0

3 years ago

Read 2 more answers

Chemistry

postnew [5]

There are 48.72 g Fluorine ions

<h3>Further explanation </h3>

Proust stated the Comparative Law that compounds are formed from elements with the same Mass Comparison so that the compound has a fixed composition of elements

In the same compound, although from different sources and formed by different processes, it will still have the same composition/comparison

%F in CaF₂ :

$\tt \%F=\dfrac{2.Ar~F}{MW~CaF_2}\times 100\%\\\\\%F=\dfrac{2.19}{78}\times 100\5=48.72\%$