Answer:
Explanation:
as we know density is g/ml or d=(g/ml) we will plug in the values in their respective positions and get the answer.
So the density is 0.812(round it according to the sig figs it asks for).
Answer:
a) FePO4(s)⇄Fe^3+(aq) + PO4^3-(aq)
b) ZnCO3(s)⇄Zn^2+(aq) + CO3^2-(aq)
c) NH4Cl(s)⇄ NH4^+(aq) + Cl^-(aq)
Explanation:
An ionic solid simply means a solid substance that is held together by ionic bonds. When an ionic substance is added to water, the ions interact with the dipoles in water and is pulled apart to form the constituent cation and anion present in the ionic solid. This is the process that we have referred to as dissolution.
The Ksp of an ionic solid is obtained from the chemical equation that shows the dissolution of an ionic solid in water. The Ksp is actually an equilibrium constant that shows the extent of dissolution of an ionic solid in water.
a) FePO4(s)⇄Fe^3+(aq) + PO4^3-(aq)
b) ZnCO3(s)⇄Zn^2+(aq) + CO3^2-(aq)
c) NH4Cl(s)⇄ NH4^+(aq) + Cl^-(aq)
Explanation:
It is known that formula for the ionization energy of hydrogen atom is as follows.
E =
or, n =
The value of energy is given as 0.544 eV. Therefore, we will calculate the value of n as follows.
n =
=
= 5
Thus, we can conclude that n equals to 5 for a hydrogen atom if 0.544 eV of energy can ionize it.
c. alpha ; neutrino. Hope it helps
Answer:
The atomic mass of the other isotope = 106.905 amu
Explanation:
Step 1: Data given
Atomic mass of silver = 107.868 amu
Ag109 isotope has an atomic mass of 108.905 amu = 48.16 %
Step 2: Calculate the abundance of the other isotope
100.0 % - 48.6 % = 51.84 %
107.868 = 0.4816*108.905 + 0.5184*X
55.419352 = 0.5184X
X = 106.905
The atomic mass of the other isotope = 106.905 amu