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Ira Lisetskai [31]
4 years ago
10

Observations of the solar system support the nebular theory because

Chemistry
2 answers:
motikmotik4 years ago
6 0

Answer:

Because all the planets orbit the sun in the same direction, along a circular flattened disk.

Explanation:

You're welcome bro, sorry for the late answer

Marina86 [1]4 years ago
6 0

Answer:

The observations that are made regarding the solar system supports the nebular theory because of the following reasons-

1) All the eight planets in the solar system move around the Sun in an anticlockwise direction. The moons of all these planets also orbit around them in the same direction, and the planets including the Sun rotate in the same way. This was believed that all these planets were formed from a disc of rock fragments rotting around the sun.

2) These planets are also observed to be configured from the disc of dust and gas particles such as hydrogen and helium, moving around the proto-sun. This hydrogen, helium gas is present only at the distant planets but are absent on the planets that are nearer to the sun. The Jovian planets are mainly composed of gases and are much bigger in size compared to the inner planets.

These are the observation that supported the nebular theory.

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2) A bubble has formed in kneaded bread dough before
EastWind [94]

Answer:  it´s c

Explanation:

4 0
3 years ago
The water lattice: a. is formed from hydrophobic bonds. b. causes ice to be denser than water. c. causes water to have a relativ
Alexus [3.1K]

Answer: Option (d) is the correct answer.

Explanation:

It is known that water loving bonds are called hydrophilic bonds and water hating bonds are called hydrophobic bonds. Since, water is a polar solvent and it is only able to dissolve polar molecules and not non-polar molecules.

Lattice of water and hydrogen bonding are responsible for the various properties of water like cohesion, adhesion, heat of vaporization etc.

Thus, we can conclude that water lattice excludes non-polar substances.

7 0
3 years ago
% Yield (10 points): 8. Using the reaction above: a. Calculate the theoretical yield of the product if you started with 5 grams
vekshin1

Answer:

a) m = 7.9 g

b) m = 3.002 g

c) butyl MgBr

Explanation:

First, you are not providing the reaction, so if difficult to solve this without it. However, I manage to find a similar question so I'm gonna solve this on basis with that question. The picture attached has the question and reaction.

Now, according to the image we have a wittig reaction. Which is commonly used to convert an aldehyde into an alcohol. As we can see in the picture, the reaction starts with hexanal and butyl MgBr (Grignard reagent) in acid medium. This gives as a product the 5-pentanol.

Let's write again the reaction here:

C₆H₁₂O + C₄H₉MgBr -----------> C₁₀H₂₂O + OHMgBr

We can see that the reaction is perfectly balanced so we don't need to balance. And we also can see that we have a mole ratio of 1:1 between the reactants and the products, which means that the calculated moles of either one reactant or the other, would be the same moles of the products.

To calculate moles, and afterward, the yield, we need the molecular weight of all compounds:

MM C₆H₁₂O = 100 g/mol

MM C₄H₉MgBr = 161.32 g/mol

MM C₁₀H₂₂O = 158 g/mol

With this given MM, let's calculate the theorical yield of the product in each case:

<u>a) 5 grams of aldehyde</u>

In this case, let's calculate the moles of the given aldehyde:

moles = 5 / 100 = 0.05 moles

Assuming this is the limiting reagent, the moles of the aldehyde would be the same moles of the product, so:

moles aldehyde = moles product = 0.05 moles

So the theorical yield would be:

m product = 0.05 * 158

<h2>m = 7.9 g of C₁₀H₂₂O</h2>

<u>b) 3 grams of butyl MgBr</u>

In this case, we will do the same thing as before, and we will assume that this is limiting reagent so:

moles = 3 / 161.32 = 0.019 moles

m C₁₀H₂₂O = 0.019 * 158

<h2>m C₁₀H₂₂O = 3.002 g</h2>

<u>c) limiting reagent</u>

Now this is easier, because if we have 5 g of aldehyde and 3 g of grignard reagent, we already has the moles of each with these masses, therefore, as both starting materials have a 1:1 mole ratio, we can see that the moles of the aldehyde are higher than the moles of grignard agent, therefore, the limiting reagent would be the butyl MgBr while the aldehyde would be the excess.

<h2>Limiting reagent = Butyl MgBr</h2>

Hope this helps

4 0
3 years ago
Hydrogen is in Group 1A of the periodic table, known as the alkali metals, although it obviously isn't a metal. What is the reas
maria [59]
The answer is a because it's electron configuration is ns1
7 0
3 years ago
Read 2 more answers
What is the empirical formula for propene (C3H6)?<br> C2H4<br> O C4H8<br> O C3H6<br> O CH2
Scilla [17]

Answer: C2H4 C4H8 C3H6.

Explanation:

3 0
3 years ago
Read 2 more answers
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