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netineya [11]
3 years ago
10

PLEASE HELPPP!!!!!!!!

Chemistry
2 answers:
svetoff [14.1K]3 years ago
7 0

Answer:

Oceanic-continental convergence---- letter B.  

Oceanic-oceanic convergence ---- letter A.

Continental-continental convergence ---- letter C

plz mark brainliest

Stells [14]3 years ago
5 0

Explanation:

Label A: oceanic - oceanic

Label B: oceanic - continental

Label C: continental - continental

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Under what condition is phase rule applied​
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Answer:

Under the equilibrium condition

Explanation:

according to the phase rule given by Willard Gibbs, under the condition where the equilibrium between the number of phases is not affected by the gravity, electricity magnetic force or by surface action and the system is under constant temperature, pressure and concentration then the degrees of freedom(F) is proportional to the concerntration (C) and the Phases(P) at equilibrium condition.  

the expression is given as : F= C-P+2

4 0
3 years ago
In a laboratory setting, chemists strive to be
Kitty [74]
Accurate and precise
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4 years ago
100.0 mL of 3.8M NaCN, the minimum lethal concentration of sodium cyanide in blood serum
9966 [12]

The given question is incomplete. The complete question is:

Calculate the number of moles and the mass of the solute in each of the following solution: 100.0 mL of 3.8 × 10−5 M NaCN, the minimum lethal concentration of sodium cyanide in blood serum

Answer: The number of moles and the mass of the solute are 0.38\times 10^{-5} and 18.62\times 10^{-5}g respectively

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute

V_s = volume of solution in ml

3.8\times 10^{-5}M=\frac{n\times 1000}{100.0}

n=0.38\times 10^{-5}

n = moles of NaCN = \frac{\text {given mass}}{\text {Molar mass}}

0.38\times 10^{-5}=\frac{x}{49g/mol}

x=18.62\times 10^{-5}g

Thus the number of moles and the mass of the solute are 0.38\times 10^{-5} and 18.62\times 10^{-5}g respectively

6 0
3 years ago
to save time you can approximate the initial volume of water to ±1 ml and the initial mass of the solid to ±1 g . for example, i
makkiz [27]

The correct answer for this question is

20.2 g silver placed in 21.6 mL of water and 12.0 g silver placed in 21.6 mL of water.

15.2 g copper placed in 21.6 mL of water and 50.0 g copper placed in 23.4 mL of water.

11.2 g gold placed in 21.6 mL of water and 14.9 g gold placed in 23.4 mL of water.

To know more about Density, click here:

brainly.com/question/6107689

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8 0
2 years ago
If an olivine liquid containing 50 weight % forsterite (Fig. 8.9) were cooled slowly until it was 50% crystallized, and then all
erik [133]

Answer:

0.35 weight fraction is liquid Forsterite and 0.65 weight fraction is liquid Fayolite

Explanation:

The lever rule is typically used to calculate the weight fractions of phases in a binary equilibrium phase diagram. It is also used in the estimation of the fraction of solid and liquid phases for a specific binary composition and temperature condition existing between the solid and liquid lines. Therefore, using the Figure. 8.9 and the use of lever rule, the composition of the remaining liquid would be 0.35 weight fraction of liquid Forsterite and 0.65 weight fraction of liquid Fayolite.

5 0
3 years ago
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