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1 year ago

Determine Δngas for each of the following reaction:(b) 2PbO(s) + O₂(g) ⇄ 2PbO₂(s)

Chemistry

1 answer:

Elis [28]1 year ago

5 0

2PbO(s) + O₂(g) ⇄ 2PbO₂(s)

Then Δngas = -1

<h3>What is Δngas?</h3>

The number of moles of gas that move from the reactant side to the product side is denoted by the symbol ∆n or delta n in this equation.

Once more, n represents the growth in the number of gaseous molecules the equilibrium equation can represent. When there are exactly the same number of gaseous molecules in the system, n = 0, Kp = Kc, and both equilibrium constants are dimensionless.

<h3>Definition of equilibrium</h3>

When a chemical reaction does not completely transform all reactants into products, equilibrium occurs. Many chemical processes eventually reach a state of balance or dynamic equilibrium where both reactants and products are present.

Learn more about Equilibrium

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What is the total ionic equation for the following reaction?

schepotkina [342]

Answer: Option (d) is the correct answer.

Explanation:

An equation in which electrolytes are represented in the form of ions is known as an ionic equation.

Strong electrolytes easily dissociate into their corresponding ions. Hence, they form ionic equation.

$H_{2}CrO_{4}$ is a strong acid and $Ba(OH)_{2}$ is a strong bases, therefore, both of them will dissociate into ions.

Thus, total ionic equation will be as follows.

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3 years ago

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Ann [662]

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3 years ago

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When 40.5 g of Al and 212.7 g of Cl2 combine in the reaction: 2 Al (s) + 3 Cl2 (g) --> 2 AlCl3 (s) c) How many moles of the e

sineoko [7]

Answer:

The answer to your question is 1.49 mol of Cl₂

Explanation:

Data

mass of Al = 40.5 g

mass of Cl₂ = 212.7 g

moles of excess reactant = ?

- Balanced chemical reaction

2 Al(s) + 3Cl₂(g) ⇒ 2AlCl₃

Process

a) Calculate the molar mass of the reactants

molar mass of Al = 2 x 26.98 = 53.96 g

molar mass of Cl₂ = 6 x 35.45 = 212.7 g

b) Calculate the theoretical proportion Al/Cl₂ = 53.96/212.7 = 0.254

Calculate the experimental proportion Al/Cl₂ = 40.5/212.7 = 0.19

As the experimental proportion is lower than the theoretical proportion we conclude that the limiting reactant is Aluminum.

c) Calculate the grams of excess reactant

53.96 g of Al ------------------ 212.7 g of Cl₂

40.5 g of Al ------------------- x

x = (40.5 x 212.7) / 53.96

x = 8614.35 / 53.96

x = 159.64 g of Cl₂

Excess Cl₂ = 212.7 - 159.64

= 53.057 g

d) Calculate the moles of Cl

35.45 g of Cl ----------------- 1 mol

53.057 g of Cl --------------- x

x = (53.057 x 1)/35.45

x = 1.49 mol of Cl₂

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3 years ago

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mojhsa [17]

Data can arranged into visual displays called graphs. There are multiple types of graphs such as bar graphs, line graphs, scatter plots, and pie charts.

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3 years ago

A when sulfuric acid is added to sirie, hydrager

irga5000 [103]

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