Ln(P2/P1) = (L/R).(1/T1 - 1/T2)
<span>with P1 = 1 atm, P2 = 45.9 atm, R = 8.314 J/mol.K, T1 = 452.15 K, T2 = 695.15 K. This gave the latent heat L as 41.2 kJ/mol.K. </span>
<span>Using this value, and calculating the vapour pressure at 120°C = 393.15 K </span>
<span>ln(P2) = (41.2 x 10^3/8.314).(1/452.15 - 1/393.15) </span>
<span>which gives the vapour pressure P2 as 0.1931 atm = 146.7 torr. </span>
I believe that the answer is B but i am not a hundred percent sure im on the same question for an exam
Explanation:
Plants are autotrophic organisms which prepare their food with the help of photosynthesis. Plants can have both asexual or multi-sexual reproduction.
Amoeba is a single celled eukaryotic organism. It moves through pseudopodia and it does not have any definite shape. Amoeba can have only asexual reproduction.
The given functions for amoeba and plants are sorted as follows.
Functions of Amoeba:
- has only offspring with identical genes and traits.
- surrounds and engulfs food particles.
- move freely in their environment.
Functions of Plants:
- makes food from carbon dioxide,water, and sunlight.
- can have offspring with different genes and traits.
Answer:
Ethane (1.09 A) > Ethene(1.076 A) > Ethyne(1.06 A)
Explanation:
The types of bonds present are:
a) Ethane : single bond
b) Ethene : double bond (one sigma one pi)
c) Ethyne: triple bond (one sigma and two pi bonds)
More the number of bonds lesser the bond length.
Thus the order of bond length of carbon-carbon bond will be:
Ethane (1.09 A) > Ethene(1.076 A) > Ethyne(1.06 A)
Answer:
so i never did this befor so i am sorry hope you get the answer
Explanation:
