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Anit [1.1K]
2 years ago
8

A chemistry student needs 60.0 g of 2-ethyltoluene for an experiment. He has available 1.5 kg of a 15.3% w/w solution of 2 ethyl

toluene in carbon tetrachloride Calculate the mass of solution the student should use. If there's not enough solution, press the "No solution" button. Round your answer to 3 significant digits.
Chemistry
1 answer:
Mila [183]2 years ago
8 0

Answer:

392 g

Explanation:

The given concentration tells us that<em> in 100 g of solution, there would be 15.3 g of 2-ethyltoluene</em>.

With that in mind we can<u> calculate how many grams of solution would contain 60.0 g of 2-ethyltoluene</u>:

  • Mass of solution * 15.3 / 100 = 60.0 g 2-ethyltoluene
  • Mass of solution = 392 g
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A gas mixture contains SO 2 SO2 ( molar mass = 64 g/mol ) (molar mass=64 g/mol) and no other source of sulfur. If the mixture is
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Explanation :

As we are given that, 10 % sulfur by mass that means 10 grams of sulfur present in 100 grams of mixture.

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Now we have to calculate the mass of SO_2.

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Thus, the mass of SO_2 is 20 grams.

Now we have to calculate the percentage (by mass) of SO_2 in the mixture.

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Therefore, the percentage (by mass) of SO_2 in the mixture is 20 %

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What is the percentage of carbon in 5.00 g of sucrose
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=:)
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Explanation: I hope this helped!

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