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astra-53 [7]
2 years ago
14

A 256 Hz tuning fork is resonating in a closed tube on a warm day when the speed of sound is 346 m/s. What is the length of the

closed tube?
A. 1.35 m
B. 0.74 m
C. 0.34 m
D. 0.18 m
Physics
1 answer:
Ilya [14]2 years ago
5 0
Assuming our "closed tube" is closed at only one end, then 
<span> v = fλ = f*4L/n 
</span><span> where "n" is the harmonic number. So 
</span><span> L = nv / 4f = n*346m/s / 4*256Hz = n*0.38 m 
</span> <span>Since the only option in your list that is an integer multiple of 0.38 m is 1.35 m
</span><span> I'd say that we're hearing the fourth harmonic. 
 answer is
 </span><span>A. 1.35 m</span><span>
  </span>
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Given:

Parallax of Regulus, p = 0.042 arc seconds

Calculation:

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Thus from the relation of parallax of a celestial body we get:

S = 1/ tan p ≈ 1 / p

where S is the actual distance between the object and the observer

            p is the parallax angle observed

Here for Regulus, we get:

S = 1 / p

  = 1 / (0.042)                                     [ 1 parsecs = 1 arcseconds ]

  = 23.81 parsecs

We know that,

1 parsecs = 3.26 light-years = 206,000 AU

Converting the actual distance into light years we get:

23.81 parsecs = 23.81 × (3.26 light yrs) = 77.658 light-years

Therefore, the actual distance of Regulus from Earth is 23.81 parsecs which is 77.658 in light years.

Learn more about astronomical units here:

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Answer:

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A ball is thrown upwards at an unknown speed. in a time of
alexandr402 [8]

Answer:

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b) At height 6 m speed of ball = 9.55 m/s

c) Maximum height reached = 10.65 m

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s = 6 m, t = 0.5 seconds, a = acceleration due to gravity value = -9.8m/s^2

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    6=u*0.5-\frac{1}{2} *9.8*0.5^2\\ \\ u=14.45m/s

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        v^2=14.45^2-2*9.8*6\\ \\ v=9.55m/s

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8 0
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F= μη

F is static force of friction.

μ is the coefficient of static friction.

η is the normal force.

6 0
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