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astra-53 [7]
3 years ago
14

A 256 Hz tuning fork is resonating in a closed tube on a warm day when the speed of sound is 346 m/s. What is the length of the

closed tube?
A. 1.35 m
B. 0.74 m
C. 0.34 m
D. 0.18 m
Physics
1 answer:
Ilya [14]3 years ago
5 0
Assuming our "closed tube" is closed at only one end, then 
<span> v = fλ = f*4L/n 
</span><span> where "n" is the harmonic number. So 
</span><span> L = nv / 4f = n*346m/s / 4*256Hz = n*0.38 m 
</span> <span>Since the only option in your list that is an integer multiple of 0.38 m is 1.35 m
</span><span> I'd say that we're hearing the fourth harmonic. 
 answer is
 </span><span>A. 1.35 m</span><span>
  </span>
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A straight segment of a current-carrying wire has a current element IL where I = 2.70 A and L = 3.20 cm i + 4.30 cm j. The segme
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The component of the force in negative z-direction is -0.144 N.

The given parameters;

  • <em>current in the wire, I = 2.7 A</em>
  • <em>length of the wire, L = (3.2 i + 4.3j) cm</em>
  • <em>magnetic filed, B = 1.24 i</em>

The force on the segment of the wire is calculated as follows;

F = ILBsin(\theta)

where;

  • <em>θ is the angle wire and magnetic field</em>

<em />

The force on the wire segment will be perpendicular in negative z-direction (applying right hand rule), so there won't be any x and y component of the force.

The angle between the wire and the magnetic field is calculated as follows;

\theta = tan^{-1} (\frac{y}{x} )\\\\\theta = tan^{-1} (\frac{4.3}{3.2} )\\\\\theta = 53.3 \ ^0

The magnitude of the wire length is calculated as follows;

|l | = \sqrt{3.2^2 + 4.3^2} = 5.36 \ cm = 0.0536 \ m

The component of the force in negative z-direction is calculated as;

F_z = -ILB sin(\theta)\\\\F_z = -2.7 \times 0.0536 \times 1.24 \times  sin(53.3)\\\\F_z = -0.144 \ N

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Learn more here:brainly.com/question/22719779

6 0
3 years ago
A block of mass 27.00 kg sits on a horizontal surface with, coefficient of kinetic
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Answer:

The force is  F  = 172 \ N

Explanation:

From the question we are told that

    The  mass of the block is  m_b  = 27.0 \ kg

     The  coefficient of  static friction is  \mu_s  =  0.65

     The coefficient of kinetic friction is  \mu_k  =  0.50

The  normal force acting on the block is  

      N  =  m *  g

substituting values

     N  =   27 *  9.8

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Given that the force we are to find is the force required to get the block to start moving then the force acting against this force is the static frictional force which is mathematically evaluated as

        F_f  =  \mu_s  *  N

substituting values

        F_f  =   0.65 *  264.6

        F_f  =   172 \ N

Now for this  block to move the force require is  equal to F_f i.e

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=>    F  = 172 \ N

       

   

5 0
3 years ago
20 POINTSSS!!!!!!!!
Soloha48 [4]
Answer: A
Hope this help you!!
7 0
3 years ago
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