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astra-53 [7]
3 years ago
14

A 256 Hz tuning fork is resonating in a closed tube on a warm day when the speed of sound is 346 m/s. What is the length of the

closed tube?
A. 1.35 m
B. 0.74 m
C. 0.34 m
D. 0.18 m
Physics
1 answer:
Ilya [14]3 years ago
5 0
Assuming our "closed tube" is closed at only one end, then 
<span> v = fλ = f*4L/n 
</span><span> where "n" is the harmonic number. So 
</span><span> L = nv / 4f = n*346m/s / 4*256Hz = n*0.38 m 
</span> <span>Since the only option in your list that is an integer multiple of 0.38 m is 1.35 m
</span><span> I'd say that we're hearing the fourth harmonic. 
 answer is
 </span><span>A. 1.35 m</span><span>
  </span>
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