answer is 46 m/s
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Which of two factors influence the weight of an object due to gravitational pull?
1 answer:
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Total displacement of the car: 405 m
Explanation:
The first part of the motion of the car is a uniformly accelerated motion, so we can use the suvat equation
where:
u = 0 is the initial velocity (the car starts from rest)
is the time elapsed in the 1st part
is the acceleration of the car in the 1st part
is the displacement of the car in the 1st part
Solving for ,
We can also find the velocity of the car after these 20 seconds using the equation:
Now we can find the distance covered by the car in the 2nd part, where it decelerates after having seen the tree limb on the road. We can do it by using the suvat equation:
where:
is the initial velocity at the beginning of the 2nd phase
is the final velocity (the car comes to a stop)
is the time elapsed in the 2nd phase
Substituting,
So, the total displacement of the car is
Learn more about accelerated motion:
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Hence ,From the Guide there are other parameters which with this equation will give the exact time the athlete's walk back
From the question we are told
If the average velocity during the athlete's walk back to the starting line in Guided Example 2.5 is – 1.50 m/s,
Generally the equation Time spent is mathematically given as
T=\frac{d}{v}
Therefore
Hence ,From the Guide there are other parameters which with this equation will give the exact time the athlete's walk back
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