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nasty-shy [4]
3 years ago
12

First answer will be made Brainliest, Jose Antonio Navarro was an important representative for Mexican Americans in Texas govern

ment and Leadership True or False​
Chemistry
1 answer:
Anika [276]3 years ago
6 0

Answer:

<h2>Jose Antonio Navarro was an important representative for Mexican Americans in Texas government and Leadership <u>True</u> </h2>

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The mineral manganosite, manganese(ll) oxide, crystallizes in the rock salt structure the face-centered structure adopted by NaC
balandron [24]

Answer:

A. 444.5 pm

Explanation:

We know that:

Density = \dfrac{mass \ of \ atoms \ in \ unit \ cell}{total \ volume \ of \ unit \ cell}

i.e.

\rho = \dfrac{n*M}{v_c * N_A}

\rho = \dfrac{n*M}{a^3 * N_A}

in a face-centered cubic crystal, the number of atoms per unit cell is (n) = 4

The molar mass of manganese (II) oxide [Mn(11)O] = 70.93 \ g/mol

Density \rho is given as 5.365 g/cm³

Avogadro constant N_A = 6.023 × 10²³ atoms/mol

∴

\rho = \dfrac{n*M}{a^3 * N_A}

Making th edge length "a" the subject, we get:

a^3 = \dfrac{n*M}{\rho* N_A}

a^3 = \dfrac{4*70.93 \ g/mol}{5.365 \ g/cm^3 *6.023 * 10^{23} \ atoms/mol }

a^3= 8.78 \times 10^{-23} \ cm^3

a= \sqrt[3]{8.78 \times 10^{-23} \ cm^3}

a = 4.445 × 10⁻⁸ cm

a = 444.5 pm

8 0
3 years ago
Evaluate the following conversion. Will the answer be correct? Explain. If incorrect, how could you adjust one of the factors to
elena55 [62]

Given :

Rate = 75 m 1 s×60 s 1 min×1 h 60 m.

To Find :

Correct answer after conversion.

Solution :

We know, 1 min = 60 sec.

1 hour = 60 min = 60×60 sec = 3600 sec.

Putting value of min and hour in seconds , we get :

R=((75\times 60) + 1 )\times ( (60 + 1)\times 60 ) \times ( 3600+3600)\ s^3\\\\R=1.186\times 10^{11} \ s^3

Hence, this is the required solution.

6 0
3 years ago
What does solubility mean?
kobusy [5.1K]
The ability to be dissolved, especially in water.
3 0
3 years ago
Read 2 more answers
Mass box A = 10 grams; Mass box B = 5 grams; Mass box C—made of one A and one B
eimsori [14]
2 boxes of A
Because C = A + B
2 of A = 20 grams
at the other hand we have 2 of B = 10
So 20 + 10 = 30 grams
3 0
4 years ago
A 0.7 ft diameter hole forms in a tank containing butane at 19 atmg and 76 degrees Fahrenheit. Determine the maximum possible ma
Aleksandr-060686 [28]

Answer:

Q = 3,534.4 lbm/s = 212,062 lbm/min

Explanation:

Mass flowrate of discharge or leakage mass flowrate (Q) is given as

Q = AC₀√(2ρgP)

A = Cross sectional Area of leakage = (πD²/4) = (π×0.7²)/4

A = 0.385 ft²

C₀ = discharge coefficient = 0.98 (For maximum discharge flow rate, the flow is turbulent with discharge coefficient within 1% of 0.98)

ρ = density of butane at 76°F = 35.771 lbm/ft³

g = acceleration due to gravity = 32.2 lbm.ft/lbf.s²

P = Gauge Pressure in the tank = (absolute pressure) - (external pressure) = 19 - 1 = 18 atm = 38091.9 lbf/ft²

Q = AC₀√(2ρgP)

Q = (0.385)(0.98)√(2×35.771×32.2×38091.9)

Q = 3,534.4 lbm/s = 212,062 lbm/min

Hope this Helps!!!

6 0
3 years ago
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