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klemol [59]
3 years ago
9

On a ring road, 12 trams are spaced at regular intervals and travel at a constant speed. How many trams need to be added to the

circuit so that, maintaining the same speed, the intervals between them will decrease by 1 5
Physics
1 answer:
Sphinxa [80]3 years ago
4 0

3 trams must be added

Explanation:

In this problem, there are 12 trams along the ring road, spaced at regular intervals.

Calling L the length of the ring road, this means that the space between two consecutive trams is

d=\frac{L}{12} (1)

In this problem, we want to add n trams such that the interval between the trams will decrease by 1/5; therefore the distance will become

d'=(1-\frac{1}{5})d=\frac{4}{5}d

And the number of trams will become

12+n

So eq.(1) will become

\frac{4}{5}d=\frac{L}{n+12} (2)

And substituting eq.(1) into eq.(2), we find:

\frac{4}{5}(\frac{L}{12})=\frac{L}{n+12}\\\rightarrow n+12=15\\\rightarrow n = 3

Learn more about distance and speed:

brainly.com/question/8893949

#LearnwithBrainly

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Three joules of work is needed to shift 10 C of charge from one place to another. The potential difference between the places is
dimaraw [331]

Answer:

The potential difference between the places is 0.3 V.

∴ 1st option i.e. 0.3V is the correct option.

Explanation:

Given

Work done W = 3J

Amount of Charge q = 10C

To determine

We need to determine the potential difference V between the places.

The potential difference between the two points can be determined using the formula

Potential Difference (V) = Work Done (W) / Amount of Charge (q)

or

\:V\:=\:\frac{W}{q}

substituting W = 3 and q = 10 in the formula

V=\frac{3}{10}

V=0.3 V

Therefore, the potential difference between the places is 0.3 V.

∴ 1st option i.e. 0.3V is the correct option.

4 0
3 years ago
Consider electrons of kinetic energy 6.0 eV and 600 keV. For each electron, find the de Broglie wavelength, particle speed, phas
irinina [24]

Answer:

For 6.0 eV

0.5 nm, 1.45*10^6 m/s, 6.17*10^10 m/s, 1.45*10^6 m/s

For 600 eV

1.26*10^-3 nm, 2.66*10^8 m/s, 3.37*10^8 m/s, 2.66*10^8 m/s

Explanation:

See attachment for calculation

5 0
4 years ago
a person, sunbathing on a warm day, is lying horizontally on the deck of a boat. her mass is 59.5 kg, and the coefficient of sta
Setler [38]

a) since a=0 therefore, friction force =0

b) friction = 59.5 × 1 =59.5 N.

c)maximum acceleration = 0.566 × g =5.54 m/s².

<h3>What is Friction force?</h3>

The force preventing sliding against one another of solid surfaces, fluid layers, and material components is known as friction. There are various kinds of friction: Two solid surfaces in touch are opposed to one another's a relative lateral motion by dry friction.

<h3>What is acceleration?</h3>

Acceleration is the rate at which an object's velocity with respect to time changes. They are vector quantities. The direction of the net force acting on an object determines the direction of its acceleration.

Hence, (a) since a=0 therefore, friction force =0, (b) friction = 59.5 × 1 =59.5 N, (c)maximum acceleration = 0.566 × g =5.54 m/s².

To know more about Friction, check out:

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4 0
1 year ago
Do all mutations result in negative affects?<br><br><br>Pls answer quick
KIM [24]

Answer:

Mutations do not necessarily always have to be bad, sometimes plants or animals mutate with something helpful to the situation they are in.

5 0
4 years ago
Which has more momentum: a 20,000 kg cement truck traveling at 5 m/s or a 1000 kg race car traveling at 90 m/s
Maurinko [17]

Hi there!

Recall the equation for momentum:
\large\boxed{p = mv}

p = linear momentum (kgm/s)
m = mass (kg)

v = velocity (m/s)

We can calculate each object's momentum and compare.

Cement truck:
p = 20000 \cdot 5 = 100000kg\frac{m}{s}

Race car:
p = 1000 \cdot 90 = 90000 kg\frac{m}{s}}

<u>Since 100,000 > 90,000, the cement truck has the greater momentum.</u>

8 0
3 years ago
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