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marin [14]
3 years ago
15

Given the amount of solute in grams and the volume of the solution in milliliters, how would you go about calculating the molari

ty of the solution?
Chemistry
1 answer:
meriva3 years ago
3 0
This is the procedure that you have to follow to calculate the molarity of the solution, given the amount of solute in grams and the volume of solutions in miliiters.


1) Formula:

 Molarity is a concentration unit that means number of moles of solute per liter of solution. This is:

M = n / V (in liters)

2) To find the number of moles you divide the mass in grams by the molar mass of the compound. This is:

n = mass in grams of soulte / molar mass of solute

3) Then, convert the volume of the solution given in mililiters to liters by dividing by 1,000. This is:

V (liters) = volume in ml / 1,000.

4) Finally, divide n by V(liters) to have M.

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A 520-gram sample of seawater contains 0.317 moles of NaCl. What is the percent composition of NaCl in the water?
Volgvan

Answer:

c

Explanation:

8 0
3 years ago
1. A student sees tiny bubbles clinging to the inside of an unopened plastic bottle full of carbonated soft drinks. The student
Lina20 [59]

Answer:

1) The bubbles will grow, and more may appear.

2)Can A will make a louder and stronger fizz than can B.

Explanation:

When you squeeze the sides of the bottle you increase the pressure pushing on the bubble, making it compress into a smaller space. This decrease in volume causes the bubble to increase in density. When the bubble increases in density, the bubble will grow and more bubbles will appear. Therefore, Changing the pressure (by squeezing the bottle) changes the volume of the bubbles. The number of bubbles doesn't change, just their size increases.

Carbonated drinks tend to lose their fizz at higher temperatures because the loss of carbon dioxide in liquids is increased as temperature is raised. This can be explained by the fact that when carbonated liquids are exposed to high temperatures, the solubility of gases in them is decreased. Hence the solubility of CO2 gas in can A at 32°C is less than the solubility of CO2 in can B at 8°C. Thus can A will tend to make a louder fizz more than can B.

3 0
3 years ago
In a neutralization reaction, 24.6 mL of 0.300 M H2SO4(aq) reacts completely with 20.0 mL of NaOH(aq). The products are Na2SO4(a
stiv31 [10]

Answer : The concentration of the NaOH solution is, 0.738 M

Explanation :

To calculate the concentration of base, we use the equation given by neutralization reaction:

n_1M_1V_1=n_2M_2V_2

where,

n_1,M_1\text{ and }V_1 are the n-factor, molarity and volume of acid which is H_2SO_4

n_2,M_2\text{ and }V_2 are the n-factor, molarity and volume of base which is NaOH.

We are given:

n_1=2\\M_1=0.300M\\V_1=24.6mL\\n_2=1\\M_2=?\\V_2=20.0mL

Putting values in above equation, we get:

2\times 0.300M\times 24.6mL=1\times M_2\times 20.0mL

M_2=0.738M

Thus, the concentration of the NaOH solution is, 0.738 M

7 0
3 years ago
Aqueous solutions of barium nitrate and potassium phosphate are mixed. What is the precipitate and how many molecules are formed
kykrilka [37]

Aqueous solutions of barium nitrate and potassium phosphate are mixed. What is the precipitate and how many molecules are formed?

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The chemical equation representing the reaction is,

            Ba(NO3)2 + K2PO4 à KNO3 + BaPO4

8 0
3 years ago
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C, a compound because it means it was made up of more than one element but, still able to be separated from the other compound(s)
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