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marin [14]
3 years ago
15

Given the amount of solute in grams and the volume of the solution in milliliters, how would you go about calculating the molari

ty of the solution?
Chemistry
1 answer:
meriva3 years ago
3 0
This is the procedure that you have to follow to calculate the molarity of the solution, given the amount of solute in grams and the volume of solutions in miliiters.


1) Formula:

 Molarity is a concentration unit that means number of moles of solute per liter of solution. This is:

M = n / V (in liters)

2) To find the number of moles you divide the mass in grams by the molar mass of the compound. This is:

n = mass in grams of soulte / molar mass of solute

3) Then, convert the volume of the solution given in mililiters to liters by dividing by 1,000. This is:

V (liters) = volume in ml / 1,000.

4) Finally, divide n by V(liters) to have M.

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Image "B" shows more biodiversity than image "A". Why?
Ilya [14]

Answer:

The answer is A

Explanation:

Image A has the same species while image B has more species than A.

8 0
3 years ago
The 54.9-g sample of the compound X2O7 contains 33.6 g of oxygen atoms. What is the molar mass of element X?
vazorg [7]
Mass of X₂O₇ = 54,9g

2x + 33,6g = 54,9g
2x = 54,9g - 33,6g
2x = 21,3g  | :2
x = 10,65g/mol
7 0
3 years ago
Read 2 more answers
If the farmer had weighed out 32.0 pounds of chicken eggs rather than kilograms what mass of quail eggs would he need to weigh o
Ira Lisetskai [31]
To have 35 pounds of quail eggs, he would need 14.5 kilograms 
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8 0
3 years ago
What is the final volume of a gas (in liters) when the initial volume is 14.00 L at
8_murik_8 [283]

Answer:

V_2=1344L

Explanation:

Hello there!

In this case, since we have a problem about volume-pressure relationship, the idea here is to use the Boyle's law to calculate the final volume as shown below:

P_2V_2=P_1V_1\\\\V_2=\frac{P_2V_2}{P_1}\\

Then, we plug in the initial and final pressures and the initial volume to obtain:

V_2=\frac{14.00L*0.9600atm}{0.01000atm}\\\\V_2=1344L

Regards!

4 0
3 years ago
What is the concentration of each ion in a solution that is prepared by dissolving 5.00 g of ammonium chloride in enough water t
const2013 [10]

Answer:

C = 0.08M

Explanation:

molar mass of AlCl3

Al =27

Cl = 35.5

27+3(35.5) =133.5g/mol

n= mass/Molar mass

n =CV

CV = mass/molar mass

C x 500 x 10^-³ = 5/133.5

C x 500 x 10^-³ = 0.04

C = 0.04/500 x 10^-³

C = 0.08M

4 0
3 years ago
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