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madam [21]
2 years ago
6

Calculate the value of the equilibrium constant for the following system, where the concentrations of reactants and products are

: [NO]=1.2x10^-3M , [NO2]=1.5x10-^1M , [N2O]=2.4x10^-3M
Chemistry
1 answer:
umka21 [38]2 years ago
5 0

Answer:

The equilibrium constant is 2.08x10⁵

Explanation:

Based on the reaction:

3NO ⇄ N₂O + NO₂

The equilibrium constant, k, is defined as:

k = [NO₂] [N₂O] / [NO]³

<em>Where the [] is the molarity in equilibrium of each specie.</em>

Computing te values of the problem:

k = [1.5x10⁻¹M] [2.4x10⁻³M] / [1.2x10⁻³M]³

k = 2.08x10⁵

<h3>The equilibrium constant is 2.08x10⁵</h3>

<em />

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Answer:

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Explanation:

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  • If n and P are constant, and have two different values of V and T:

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<em></em>

V₁ = 634.0 L, T₁ = 21.0°C + 273 = 294.0 K.

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233.1g

Explanation:

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