Vf=√30²+100²
Vf=104 m/s
|Ф|=tan inverse of |100÷30|
Ф= 73 degrees
Therefore the resulting velocity of the airplaine is 104 m/s [ 73 degrees N of W]
No electron with a de Broglie wavelength of 2 μm can not pass through a slit that is 1 μm wide
When studying quantum mechanics, the de Broglie wavelength is a key idea. De Broglie wavelength is the wavelength () that is connected to an item in relation to its momentum and mass. Typically, a particle's force is inversely proportional to its de Broglie wavelength.
Where "h" is the Plank constant, momentum has the formula = h m v = h. The de Broglie equation and de Broglie wavelength are terms used to describe the relationship between a particle's momentum and wavelength. The probability density of locating an object at a specific location in the configuration space is determined by the De Broglie wavelength, which is a wavelength present in all quantum mechanical objects. A particle's momentum and de Broglie wavelength are inversely related.
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Answer:
θ = 12.60°
Explanation:
In order to calculate the angle below the horizontal for the velocity of the hockey puck, you need to calculate both x and y component of the velocity of the puck, and also you need to use the following formula:
(1)
θ: angle below he horizontal
vy: y component of the velocity just after the puck hits the ground
vx: x component of the velocity
The x component of the velocity is constant in the complete trajectory and is calculated by using the following formula:

vo: initial velocity = 28.0 m/s
The y component is calculated with the following equation:
(2)
voy: vertical component of the initial velocity = 0m/s
g: gravitational acceleration = 9.8 m/s^2
y: height
You solve the equation (2) for vy and replace the values of the parameters:

Finally, you use the equation (1) to find the angle:

The angle below the horizontal is 12.60°
The spring constant of the given spring is 250 N/m. Spring constant is the measure of the stiffness of the spring.
<h3>
What is the spring constant?</h3>
It is the measure of the stiffness of the spring or in other work how much a spring resists the deformation.
From Hooke's law,

- force - 75 N
- spring constant
- displacement - 0.3 m
Put the values in the formula and calculate for
,

Therefore, the spring constant of the given spring is 250 N/m.
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