Complete Question:
A 10 kg block is pulled across a horizontal surface by a rope that is oriented at 60° relative to the horizontal surface.
The tension in the rope is constant and equal to 40 N as the block is pulled. What is the instantaneous power (in W) supplied by the tension in the rope if the block when the block is 5 m away from its starting point? The coefficient of kinetic friction between the block and the floor is 0.2 and you may assume that the block starting at rest.
Answer:
Power = 54.07 W
Explanation:
Mass of the block = 10 kg
Angle made with the horizontal, θ = 60°
Distance covered, d = 5 m
Tension in the rope, T = 40 N
Coefficient of kinetic friction,
Let the Normal reaction = N
The weight of the block acting downwards = mg
The vertical resolution of the 40 N force,
Power,
Meters ?? or just a variable
Answer:
All steps are 20 * 100 (break the rest into appropriate pieces)
You can multiply as follows
(2000) * ((3 * 60) + (2 * 60) + 60)
V = 2000 * 6 * 60) = 720,000 cm^3 = .72 m^3
.72 m^3 * 2400 kg / m^3 = 1728 kg
Answer:
2,4,5
Air pressure is created by the weight of the atmosphere pushing on Earth’s surface.
Denser air is heavier than less dense air.
Air is less dense at higher altitudes.
Answer:
C) is zero
Explanation:
According to the law of energy conservation, the total mechanical energy of the object is conserved. A book falling a distance d would have a change in potential energy, resulting in the same change in kinetic energy. But the total mechanical energy must be the same. So there's 0 change in total energy of the system.