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vlabodo [156]
3 years ago
11

How much heat is required to evaporate 0.15 kg of lead at 1750°C, the boiling point for lead? The heat of vaporization for lead

is Lv = 871 × 103 J/kg.
Physics
1 answer:
lara [203]3 years ago
3 0

Answer:

Heat required = mass× latent heat Q = 0.15 × 871 ×

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