Answer:
vDP = 21.7454 m/s
θ = 200.3693°
Explanation:
Given
vDE = 7.5 m/s
vPE = 20.2 m/s
Required: vDP
Assume that
vDE to be in direction of - j
vPE to be in direction of i
According to relative motion concept the velocity vDP is given by
vDP = vDE - vPE (I)
Substitute in (I) to get that
vDP = - 7.5 j - 20.2 i
The magnitude of vDP is given by
vDP = √((- 7.5)²+(- 20.2)²) m/s = 21.7454 m/s
θ = Arctan (- 7.5/- 20.2) = 20.3693°
θ is in 3rd quadrant so add 180°
θ = 20.3693° + 180° = 200.3693°
Answer:

Explanation:
Given that:

R = (0.1) m
To find the electric field for r < R by using Gauss Law

For r < R



where;




The central force acting on the electron as it revolves in a circular orbit is
.
The given parameters;
- <em>speed of electron, v = 2.2 x 10⁶ m/s</em>
- <em>radius of the circle, r = 4.63 x 10⁻¹¹ m</em>
<em />
The central force acting on the electron as it revolves in a circular orbit is calculated as follows;

where;
is mass of electron = 9.11 x 10⁻³¹ kg

Thus, the central force acting on the electron as it revolves in a circular orbit is
.
Learn more about centripetal force here:brainly.com/question/20905151
The two fields were physical quantities are used in motion calculations are length and mass with time.
The physical quantity in a field is referred as every point in a particular space time.
<h3>
How physical quantities are used in motion calculations?</h3>
If we consider an object, the physical property of the object is considered as physical quantity and to measure that object is known as units. The Physical quantity can be classified as elemental physical quantity and derived physical quantity. Length, mass, time, etc.. are elemental physical quantity, momentum, density, acceleration, etc... are derived physical quantity. Only for charge and temperature the physical quantity will be less than zero.
Length, mass and time are the physical quantities used in motion calculations.
Learn more about motion calculations,
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Answer:
the correct one is C
Explanation:
For this exercise we must use the work definition
W = F. s
Where the bold characters indicate vectors and the point is the scalar producer
W = F s cos θ
Where θ is the angles between force and displacement.
Let us support this in our case. The cable creates an upward tension and with the elevator going down the angle between them is 180º so the work of the cable on the elevator is negative.
The evade has a downward force, its weight so the force goes down and the displacement goes down, as both are in the same direction the work is positive
When examining the statements the correct one is C