Answer:
The work done on the canister is 15.34 J.
Explanation:
Given;
mass of canister, m = 1.9 kg
magnitude of force acting on x-y plane, F = 3.9 N
initial velocity of canister in positive x direction, = 3.9 m/s
final velocity of the canister in positive y direction,
The change in the kinetic energy of the canister is equal to net work done on the canister by 3.9 N.
ΔK.E =
ΔK.E
The initial kinetic energy of the canister;
The final kinetic energy of the canister;
ΔK.E = 29.79 J - 14.45 J
ΔK.E = = 15.34 J
Therefore, the work done on the canister is 15.34 J.