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gizmo_the_mogwai [7]
3 years ago
8

A solid conducting sphere is placed in an external uniform electric field. With regard to the electric field on the sphere's int

erior, which statement is correct? A solid conducting sphere is placed in an external uniform electric field. With regard to the electric field on the sphere's interior, which statement is correct? The interior field points in a direction perpendicular to the exterior field. The interior field points in a direction opposite to the exterior field. There is no electric field on the interior of the conducting sphere. The interior field points in a direction parallel to the exterior field.
Physics
2 answers:
Pepsi [2]3 years ago
7 0

There is no electric field on the interior of the conducting sphere..

Gala2k [10]3 years ago
5 0

Answer:

There is no electric field on the interior of the conducting sphere.

Explanation:

When conducting sphere is placed in external electric field then as we know that all conductors will have large amount of free charge present inside the conductor, this free charge will experience force due to this external electric field and start rearrange itself.

This rearrangement of charge is known as induction in conductors

This rearrangement will continue takes place till the electric field due to this rearrangement of charge will counterbalance the external electric field.

So at the steady state position the net electric field inside all conductors must be zero

so here correct answer would be

There is no electric field on the interior of the conducting sphere.

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Would electromagnetic waves exist if changing magnetic fields could produce electric fields but changing electric fields could n
-Dominant- [34]

Answer:

No electromagnetic waves can not exists if changing magnetic field could produce electric fields but the changing electric fields could not produce magnetic fields. Electromagnetic waves are oscillating waves and they are based on this fact that the changing magnetic field produce electric field and the changing electric field produce the magnetic field. That is why these waves are known for self propagation and can even travel through vacuum. In this wave the electric field and the magnetic field lies perpendicular to each other. These waves travel with the speed of light and their example is light and other radiations coming from sun.

7 0
3 years ago
A man pushes with a force of 200 N on a bookcase of mass 80 kg. The
alexandr402 [8]

Answer: 200 N

Explanation: Apex

7 0
4 years ago
9. Captain America is chasing Red Skull. He plans to throw his shield to knock down Red Skull but needs to know how fast Red Sku
Sedaia [141]

Red Skull's relative velocity to Captain America, towards the left front of the

truck is approximately <u>33.23 m/s</u> in a direction from the North of

approximately <u>9.18°</u>.

Reasons:

Assumptions;

Taking the north direction as positive.

The activity takes place on the trucks.

The trucks are moving towards each other.

Solution:

Vector form of net speed of Red Skull, is given as follows;

  • v₁ = -(\frac{\sqrt{2} }{2} × 3.5)·i + (\frac{\sqrt{2} }{2} × 3.5 + 12.5)·j

Vector form of the net speed of Captain America is given as follows;

  • v₂ =  (\frac{\sqrt{2} }{2} × 4.0)·i - (\frac{\sqrt{2} }{2} × 4.0 + 15)·j

Relative velocity, v₁₂ = v₁ - v₂

∴ v₁₂ = (-(\frac{\sqrt{2} }{2} × 3.5) - (\frac{\sqrt{2} }{2} × 4.0))·i + ((\frac{\sqrt{2} }{2} × 3.5 + 12.5) + (\frac{\sqrt{2} }{2} × 4.0 + 15))·j

  • v₁₂ = -\frac{ 15 \cdot \sqrt{2} }{4}·i + \frac{ 110 + 15 \cdot \sqrt{2} }{4}·j

Red Skull's velocity relative to Captain America,  v₁₂ = -\frac{ 15 \cdot \sqrt{2} }{4}·i + \frac{ 110 + 15 \cdot \sqrt{2} }{4}·j

  • v₁₂ ≈ -5.3·i + 32.8·j

Therefore;

  • Red Skull appears to be moving West at <u>5.3 m/s</u> and North at <u>32.8 m/s</u>

  • The direction is arctan \left(\frac{32.8}{-5.3} \right) \approx -80.2^{\circ}

Therefore;

  • Red Skull appear to be moving at 90° - 80.2° ≈ 9.18° towards the left front end of the truck moving North

The magnitude of the velocity, |v₁₂|, is given as follows;

  • |v_{12}| = \sqrt{\left(-\frac{ 15 \cdot \sqrt{2} }{4}\right)^2 + \left(\frac{ 110 + 15 \cdot \sqrt{2} }{4}\right)^2} = \dfrac{ 5 \cdot \sqrt{130+33 \cdot\sqrt{2} } }{2} \approx 33.23·

The magnitude of Red Skull's velocity relative to Captain America is,

therefore;

|v₁₂| ≈ <u>33.23 m/s</u>

Learn more here:

brainly.com/question/24430414

6 0
3 years ago
A dinner plate falls vertically to the floor and breaks up into three pieces, which slide horizontally along the floor. Immediat
N76 [4]

Answer:

p_k=\sqrt{p_x^2+p_y^2}}

Explanation:

Apply the momentum in each direction knowing that the impact is at the same time for the pieces so

p_x=m_1*v_1

p_x=200g*2.0m/s=0.4kgm/s

p_y=m_2*v_2

p_y=235g*1.5m/s=0.3525kgm/s

So the momentum in the other piece can be find knowing that

p_x^2+p_y^2=p_k^2

So:

p_k=\sqrt{p_x^2+p_y^2}}

p_k=\sqrt{0.4^2+0.3525^2}}=\sqrt{0.2842 kg^2*m^2/s^2}

p_k=0.5331kg*m/s

To find the velocity knowing the mass

p_k=m_k*v_k

v_k=\frac{p_k}{m_k}=\frac{0.5331 kg*m/s}{0.10kg}

v_k=5.331 m/s

4 0
3 years ago
What is a resultant vectors direction?
mart [117]
That completely depends on all sizes and all directions of all of the vectors that combined to produce the resultant one.
8 0
4 years ago
Read 2 more answers
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