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Tanya [424]
3 years ago
7

what is the measure of angle 3 if the measure of angle 6 is (2x-5) and the measure of angle 8 is (x+5)?

Mathematics
1 answer:
strojnjashka [21]3 years ago
4 0

Answer: 115

Step-by-step explanation: just did it on edg

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What is the slope of these two equations?
Juli2301 [7.4K]

Answer:

8. 0

9. undefined

Step-by-step explanation:

8. 0

> because the y variable is the same for all x-values, this is a horizontal line. Horizontal lines have a slope of 0.

  > <em>Thinking of slope as rise over run: we will always rise 0, and run __ from any two points--0 divided by any number is always 0</em>

9. undefined

> because the x variable is always the same, no matter what y variable we graph, we will have the same outcome. So, this would look like a straight line, which have an undefined slope.

   > <em>If you think of a slope as rise / run; if you go from any two points, there will be a 0 in the denominator--which is undefined</em>

<em />

<em />

hope this helps!! have a lovely day :)

3 0
2 years ago
The functions f and g are defined by these sets if input and output values.
erastovalidia [21]
(x,y)
x=input
y=output
example
we see
g=(1,2)
theefor
g(1)=2


a.
f(4)=1
g(1)=2
g(f(4))=2

b.
g(-2)=4
f(4)=1
f(g(-2))=1

c.
f(3)=5
g(5)=5
f(5)=0
f(g(f(3)))=0
5 0
3 years ago
6 x (12-2) + 2 to the power of 2​
liubo4ka [24]

Answer:

84x

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
A rectangle has a length of x + 7 and a width of x-2. Which equation below describes the perimeter, P, of
valkas [14]

Answer:

            P = 4x  +  10

Step-by-step explanation:

perimeter of a rectangle = 2( width + length )

   P = 2 ( x - 2  +  x + 7 )

   P = 2 ( x + x  +  7 - 2 )

        P = 2 ( 2x +  5 )

            P = 4x  +  10

4 0
3 years ago
A tank contains 30 lb of salt dissolved in 500 gallons of water. A brine solution is pumped into the tank at a rate of 5 gal/min
Dmitry [639]

At any time t (min), the volume of solution in the tank is

500\,\mathrm{gal}+\left(5\dfrac{\rm gal}{\rm min}-5\dfrac{\rm gal}{\rm min}\right)t=500\,\mathrm{gal}

If A(t) is the amount of salt in the tank at any time t, then the solution has a concentration of \dfrac{A(t)}{500}\dfrac{\rm lb}{\rm gal}.

The net rate of change of the amount of salt in the solution, A'(t), is the difference between the amount flowing in and the amount getting pumped out:

A'(t)=\left(5\dfrac{\rm gal}{\rm min}\right)\left(\left(2+\sin\dfrac t4\right)\dfrac{\rm lb}{\rm gal}\right)-\left(5\dfrac{\rm gal}{\rm min}\right)\left(\dfrac{A(t)}{50}\dfrac{\rm lb}{\rm gal}\right)

Dropping the units and simplifying, we get the linear ODE

A'=10+5\sin\dfrac t4-\dfrac A{10}

10A'+A=100+50\sin\dfrac t4

Multiplying both sides by e^{10t} allows us to identify the left side as a derivative of a product:

10e^{10t}A'+e^{10t}A=\left(100+50\sin\dfrac t4\right)e^{10t}

\left(e^{10}tA\right)'=\left(100+50\sin\dfrac t4\right)e^{10t}

e^{10t}A=\displaystyle\int\left(100+50\sin\dfrac t4\right)e^{10t}\,\mathrm dt

Integrate and divide both sides by e^{10t} to get

A(t)=10-\dfrac{200}{1601}\cos\dfrac t4+\dfrac{8000}{1601}\sin\dfrac t4+Ce^{-10t}

The tanks starts off with 30 lb of salt, so A(0)=30 and we can solve for C to get a particular solution of

A(t)=10-\dfrac{200}{1601}\cos\dfrac t4+\dfrac{8000}{1601}\sin\dfrac t4+\dfrac{32,220}{1601}e^{-10t}

6 0
3 years ago
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