Using the formula F=ma
500N=50kg (a)
a= 10 m/s^2
Answer:
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The magnetic dipole moment of the current loop is 0.025 Am².
The magnetic torque on the loop is 2.5 x 10⁻⁴ Nm.
<h3>What is magnetic dipole moment?</h3>
The magnetic dipole moment of an object, is the measure of the object's tendency to align with a magnetic field.
Mathematically, magnetic dipole moment is given as;
μ = NIA
where;
- N is number of turns of the loop
- A is the area of the loop
- I is the current flowing in the loop
μ = (1) x (25 A) x (0.001 m²)
μ = 0.025 Am²
The magnetic torque on the loop is calculated as follows;
τ = μB
where;
- B is magnetic field strength
B = √(0.002² + 0.006² + 0.008²)
B = 0.01 T
τ = μB
τ = 0.025 Am² x 0.01 T
τ = 2.5 x 10⁻⁴ Nm
Thus, the magnetic dipole moment of the current loop is determined from the current and area of the loop while the magnetic torque on the loop is determined from the magnetic dipole moment.
Learn more about magnetic dipole moment here: brainly.com/question/13068184
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Answer:
Ep = 117600 J
Explanation:
Data:
- Mass (m) = 600 kg
- Height (h) = 20 m
- Gravity (g) = 9.8 m/s²
- Potential Energy (Ep) = ?
Use formula:
Replace:
- Ep = 600 kg * 9.8 m/s² * 20 m
Multiply operations, and units:
What is the potential energy?
The potential energy is <u>117600 Joules.</u>
Answer:
-24.28571 rad/s²
29.57239 revolutions
3.91176 seconds
52.026478 m
Explanation:
= Tangential acceleration = -6.8 m/s²
r = Radius of wheel = 0.28
= Initial angular velocity = 95 rad/s
= Angle of rotation
= Final angular velocity
t = Time taken
Angular acceleration is given by
The angular acceleration is -24.28571 rad/s²
The number of revolutions is 29.57239
The time it takes for the car to stop is 3.91176 seconds
Linear distance
The distance the car travels is 52.026478 m
