Two flat surfaces are exposed to a uniform, horizontal magnetic field of magnitude 0.47 T. When viewed edge-on, the first surfac
1 answer:
Answer:
a. A = 0.0859 m^2
b. A = 0.0178 m^2
Explanation:
Two flat surfaces are exposed to a uniform, horizontal magnetic field of magnitude 0.47 T. When viewed edge-on, the first surface is tilted at an angle of from the horizontal, and a net magnetic flux of 8.4 103 Wb passes through it. The same net magnetic flux passes through the second surface. (a) Determine the area of the first surface. (b) Find the smallest possible value for the area of the second surface.
take note that the question has not specified th angle which the surface is tilted so i assume the angle is at to the horizontal
flux = BAcos()
B=magnetic flux in Weber
A=area of the flat surface in m^2
=the angle to the horizontal
a) 8.4 x10^-3= (.47)Acos(78)
alpha has to be the angle from the normal and not the horizontal so 90-12=78,
8.4 x10^-3
/(.47)cos(78)
A = 0.0859 m^2
b) If flux remains the same then for it to be the smallest possible area it needs to be perpendicular to the magnetic field so alpha would be 0.
8.4 x10^-3 = (.47)Acos(0)
A = 0.0178 m^2
You might be interested in
Initial speed = 2√10 m/s
<h3>Further explanation </h3>Linear motion consists of 2: constant velocity motion with constant velocity and uniformly accelerated motion with constant acceleration
An equation of uniformly accelerated motion
V = vo + at
Vt² = vo² + 2a (x-xo)
x = distance on t
vo / vi = initial speed
vt / vf = speed on t / final speed
a = acceleration
vf=20 m/s
d = 60 m
a = 3 m/s²
Here is the full question.
Saturated ethylene glycol at 1 atm is heated by a chromium-plated surface which is circular in shape and has a diameter of 200-mm and is maintained at 480 K.
At 470 K the properties of the saturated liquid are mu = 0.38 * 10-3 N. s/m^2, Cp = 3280 J/kg. K and Pr = 8.7. The saturated vapour density is p= 1.66 kg/m^3. Take the liquid to surface constants to be Cnb = 0.010 and m=4.1.
Estimate the heating power requirement and the rate of evaporation
What fraction is the power requirement of the maximum power associated with the critical heat flux
Answer:
The heating power requirement = 559.2 W
The rate of evaporation =
The fraction of the power requirement of operating heat flux to the maximum power associated with the critical heat flux is = 0.026
Explanation:
From the thermodynamics tables; we deduced the value for enthalpy at the pressure 1 atm and = 470 K for the saturated ethylene glycol.
Value for enthalpy of formation = 812 kJ/kg
Density of saturated ethylene glycol = 1111 kg/m³
Surface tension
The heat flux can be calculated by using the formula:
= 308.56 × 576.6 × 0.1
= 1.78 × 10⁴ W/m²
Now; to find the heating power requirement; we have:
=
Thus, the heating power requirement = 559.2 W
The rate of evaporation is given as:
=
=
Thus, the rate of evaporation =
To determine to what fraction in the power requirement of the maximum power is associated with the critical total flux ; we needed to first calculate the critical heat flux.
So, the calculation for the critical heat is given as:
=
= 200840.08 × 3.37
= 6.77 × 10⁵ W/m²
Finally, the fraction of the power requirement of operating heat flux to the maximum power associated with the critical heat flux is as follows:
=
=
= 0.026
Thus, the fraction of the power requirement of operating heat flux to the maximum power associated with the critical heat flux is = 0.026
Answer:
this is what I found, hope it helps!
